【C++】函数和指针

double pam(int); //参数为int 类型，返回值为double 类型的函数
double (*pf);(int)  //指向参数为int类型,返回值为double 类型的指针
pf = pam;   //函数名代表了函数的地址

double x = pam(4); //函数名调用
double x = (*pf)(4); //指针调用
double x = pf(4); //C++也允许将指针名当作函数名使用

const double * f1(const double *, int);

const double * (*p1)(const double *, int); //p1 poitns to f1
auto p2 = f1; //C++11 automatic type deduction,p2 points to f1 as well

//前面函数为double *类型，cout第一部分返回double指针，第二部分返回double指针指向的值
cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl;
//和上面的cout一样只不过是使用函数指针名来调用函数
cout<<p2(av,3)<<":"<<*p2(av,3)<<endl;

const double *(*pa[3]) (const double *,int) = {f1,f2,f3}; //创建函数指针数组
//通过指针调用函数，得到返回的指针
const double *px = pa[0](av,3); //call by pointer as if it were a function name
const double *py = (*pa[0])(av,3); //正常调用

//得到函数返回指针指向的值
double x = *pa[0](av,3);
double x = *(*pa[0])(av,3);

*pd[3] //an array of 3 pointers
(*pd)[3] //a pointer to an array of three elements

1 auto pc = &pa;   //&pa是整个数组的地址, pa是数组第一个元素首地址
2  
3 const double * (*(*pd)[3])(const double *,  int ) = &pa; //和第一个等价
4 
5 **&pa = *pa = pa[0]

 1 //arfupt.cpp -- an array of function pointers
 2 #include<iostream>
 3 //various notations,same signatures
 4 const double *f1(const double ar[],int n);
 5 const double *f2(const double [],int);
 6 const double *f3(const double *,int);
 7 
 8 int main()
 9 {
10     using namespace std;
11     double av[3] = {1112.3,1542.6,2227.9};
12 
13     //pointer to a function
14 
15     const double *(*p1)(const double *,int) = f1;
16     auto p2 = f2;//C++ 11 utomatic  type deduction
17     //pre-C++11 can use the following code instead
18     //const double *(*p2)(const double *,int) = f2;
19     cout<<"Using pointers to functions:\n";
20     cout<<"Address Value\n";
21     cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl;
22     cout<<p2(av,3)<<":"<<*p2(av,3)<<endl;
23 
24     //pa an array of pointers
25     //auto doesn‘t work with list initialization
26     const double *(*pa[3])(const double *,int) = {f1,f2,f3};
27     //pb a pointer to first element of pa
28     auto pb = pa;
29     // pre-C++11 can use the following code instead
30     // const double *(**pb)(const double *, int) = pa;
31     cout<<"\nUsing an array of pointers to functions:\n";
32     cout<<"Address Value\n";
33     for(int i = 0;i < 3; i++)
34         cout<<pa[i](av,3)<<":"<<*pa[i](av,3)<<endl;
35     cout<<"\nUsing a pointer to a pointer to a function:\n";
36     cout<<"Address Value\n";
37     for(int i = 0;i < 3; i++)
38         cout<<pb[i](av,3)<<":"<<*pb[i](av,3)<<endl;
39 
40     //what about a pointer to an array of function pointers
41     cout<<"\nUsing pointers to an array of pointers:\n";
42     cout<<"Address Value\n";
43     //easy way to declare pc
44     auto pc = &pa;
45     // pre-C++11 can use the following code instead
46     // const double *(*(*pc)[3])(const double *, int) = &pa;
47     cout<<(*pc)[0](av,3)<<":"<<*(*pc)[0](av,3)<<endl;
48     //hard way to declare pd
49     const double *(*(*pd)[3])(const double *,int) = &pa;
50     //store return value in pdb
51     const double *pdb = (*pd)[1](av,3);
52     cout<<pdb<<":"<<*pdb<<endl;
53     //alternative notation
54     cout<<(*(pd)[2])(av,3)<<":"<<*(*(*pd)[2])(av,3)<<endl;
55 }
56 
57 const double * f1(const double * ar, int n)
58 {
59 return ar;
60 }
61 const double * f2(const double ar[], int n)
62 {
63 return ar+1;
64 }
65 const double * f3(const double ar[], int n)
66 {
67 return ar+2;
68 }