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PYTHON设计模式学习(3):Singleton pattern

时间:2017-08-01 14:34:43      阅读:192      评论:0      收藏:0      [点我收藏+]

标签:ret   python   attr   bsp   对象   ghost   on()   metaclass   span   

参考了其他的博客:http://ghostfromheaven.iteye.com/blog/1562618

#-*- encoding=utf-8 -*-  
print ----------------------方法1--------------------------  
#方法1,实现__new__方法  
#并在将一个类的实例绑定到类变量_instance上,  
#如果cls._instance为None说明该类还没有实例化过,实例化该类,并返回  
#如果cls._instance不为None,直接返回cls._instance  
class Singleton(object):  
    def __new__(cls, *args, **kw):  
        if not hasattr(cls, _instance):  
            orig = super(Singleton, cls)  
            cls._instance = orig.__new__(cls, *args, **kw)  
        return cls._instance  
  
class MyClass(Singleton):  
    a = 1  
  
one = MyClass()  
two = MyClass()  
  
two.a = 3  
print one.a  
#3  
#one和two完全相同,可以用id(), ==, is检测  
print id(one)  
#29097904  
print id(two)  
#29097904  
print one == two  
#True  
print one is two  
#True  
  
print ----------------------方法2--------------------------  
#方法2,共享属性;所谓单例就是所有引用(实例、对象)拥有相同的状态(属性)和行为(方法)  
#同一个类的所有实例天然拥有相同的行为(方法),  
#只需要保证同一个类的所有实例具有相同的状态(属性)即可  
#所有实例共享属性的最简单最直接的方法就是__dict__属性指向(引用)同一个字典(dict)  
#可参看:http://code.activestate.com/recipes/66531/  
class Borg(object):  
    _state = {}  
    def __new__(cls, *args, **kw):  
        ob = super(Borg, cls).__new__(cls, *args, **kw)  
        ob.__dict__ = cls._state  
        return ob  
  
class MyClass2(Borg):  
    a = 1  
  
one = MyClass2()  
two = MyClass2()  
  
#one和two是两个不同的对象,id, ==, is对比结果可看出  
two.a = 3  
print one.a  
#3  
print id(one)  
#28873680  
print id(two)  
#28873712  
print one == two  
#False  
print one is two  
#False  
#但是one和two具有相同的(同一个__dict__属性),见:  
print id(one.__dict__)  
#30104000  
print id(two.__dict__)  
#30104000  
  
print ----------------------方法3--------------------------  
#方法3:本质上是方法1的升级(或者说高级)版  
#使用__metaclass__(元类)的高级python用法  
class Singleton2(type):  
    def __init__(cls, name, bases, dict):  
        super(Singleton2, cls).__init__(name, bases, dict)  
        cls._instance = None  
    def __call__(cls, *args, **kw):  
        if cls._instance is None:  
            cls._instance = super(Singleton2, cls).__call__(*args, **kw)  
        return cls._instance  
  
class MyClass3(object):  
    __metaclass__ = Singleton2  
  
one = MyClass3()  
two = MyClass3()  
  
two.a = 3  
print one.a  
#3  
print id(one)  
#31495472  
print id(two)  
#31495472  
print one == two  
#True  
print one is two  
#True  
  
print ----------------------方法4--------------------------  
#方法4:也是方法1的升级(高级)版本,  
#使用装饰器(decorator),  
#这是一种更pythonic,更elegant的方法,  
#单例类本身根本不知道自己是单例的,因为他本身(自己的代码)并不是单例的  
def singleton(cls, *args, **kw):  
    instances = {}  
    def _singleton():  
        if cls not in instances:  
            instances[cls] = cls(*args, **kw)  
        return instances[cls]  
    return _singleton  
 
@singleton  
class MyClass4(object):  
    a = 1  
    def __init__(self, x=0):  
        self.x = x  
  
one = MyClass4()  
two = MyClass4()  
  
two.a = 3  
print one.a  
#3  
print id(one)  
#29660784  
print id(two)  
#29660784  
print one == two  
#True  
print one is two  
#True  
one.x = 1  
print one.x  
#1  
print two.x  
#1

 

PYTHON设计模式学习(3):Singleton pattern

标签:ret   python   attr   bsp   对象   ghost   on()   metaclass   span   

原文地址:http://www.cnblogs.com/aomi/p/7267986.html

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