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python之itemgetter函数:对字典列表进行多键排序

时间:2017-08-05 22:48:45      阅读:612      评论:0      收藏:0      [点我收藏+]

标签:alice   默认   排列   log   opera   int   字典   person   for   

itemgetter函数:对字典列表进行多键排序

 1 from operator import itemgetter
 2 
 3 list_people = [
 4     {name: Mike, age: 22, score: 90},
 5     {name: Alice, age: 22, score: 90},
 6     {name: Lee, age: 26, score: 92},
 7     {name: Ben, age: 26, score: 85},
 8     {name: Tom, age: 33, score: 90},
 9     {name: Jill, age: 41, score: 72}
10 ]
11 
12 print(根据名字排序:)
13 for i in sorted(list_people, key=lambda person: person[name]):
14     ‘‘‘sorted()函数默认升序排列‘‘‘
15     print(i)
16 
17 print(\n根据得分降序排列:)
18 for i in sorted(list_people, key=itemgetter(score), reverse=True):
19     ‘‘‘参数reverse=True表示降序排列‘‘‘
20     print(i)
21 
22 print(\n根据名字和年龄多键排序:)
23 for i in sorted(list_people, key=itemgetter(name, age)):
24     print(i)

运行结果:

1 根据名字和年龄多键排序:
2 {name: Alice, age: 22, score: 90}
3 {name: Ben, age: 26, score: 85}
4 {name: Jill, age: 41, score: 72}
5 {name: Lee, age: 26, score: 92}
6 {name: Mike, age: 22, score: 90}
7 {name: Tom, age: 33, score: 90}

 

python之itemgetter函数:对字典列表进行多键排序

标签:alice   默认   排列   log   opera   int   字典   person   for   

原文地址:http://www.cnblogs.com/gongxr/p/7291714.html

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