标签：python初学者
要求：
输入用户名密码
认证成功后显示欢迎信息
输错三次后锁定
本程和作业要求稍有不同，当用户输入三次相同的用户名且无法登陆时锁定该用户名。
下面也会附上符合题目要求的代码，但是存在一个Bug，就是输入三次无法正确登陆只会锁定最后一次输入的用户名。
程序一：
#！usr/bin/evn python
#-*-coding utf-8 -*-
__author__ = ‘Galen‘
import getpass as gp#引入getpass模块
import pickle#引入pickle模块，pickle提供了一个简单的持久化功能。可以将对象以文件的形式存放在磁盘上。
import os
#验证是否存在保存被锁定用户的文件，如果没有则创建一个空的文件，并写入一个空的列表
if not os.path.exists("F:/AAAA资料/Python程序/Python3.5-零基础-高级-完整项目剖析/第1周/lock_user.txt"):
lock_user_file = open("lock_user.txt","wb")
lock_user = []
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()
#定义事先设定的username和password常亮
_username ="Galen"
_password = "Galen"
inpu_user = {}#创建一个空的字典，用于判断一个用户名输入了几遍
count = 0#用于记录输入的次数
while count<3:
print("第{}次输入".format(count+1))
username = input("username：")
if username not in inpu_user:
inpu_user[username]=0
#读取文件
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user_file.close()
#验证输入的用户是否已经被锁定
if username not in lock_user:
password = gp.getpass("password:")
if username == _username and password == _password:
print("Welocme {} come back".format(username))
count +=1
inpu_user[username] +=1
break
else:
print("you are illegal user")
count +=1
inpu_user[username] +=1
else:
#如果输入的用户被锁定，可以通过验证解除锁定
print("You have been locked,please contact with administrators")
#
if input("Are you want to contact administrators :") =="y":
if input("Please input your ide_code : ") =="Galen":
#输入输入验证码正确则，删除被锁用户名
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user.remove(username)
lock_user_file = open("lock_user.txt","wb")
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()
else:
print("You have lost the last chance")
break
#如果连续输入三次未登陆则锁定用户
if inpu_user[username]==3:
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user.append(username)
lock_user_file = open("lock_user.txt","wb")
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()程序二：
#！usr/bin/evn python
#-*-coding utf-8 -*-
__author__ = ‘Galen‘
import getpass as gp#引入getpass模块
import pickle
import os
#验证是否存在保存被锁定用户的文件，如果没有则创建一个空的文件，并写入一个空的列表
if not os.path.exists("F:/AAAA资料/Python程序/Python3.5-零基础-高级-完整项目剖析/第1周/lock_user.txt"):
lock_user_file = open("lock_user.txt","wb")
lock_user = []
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()
#定义事先设定的username和password常亮
_username ="Galen"
_password = "Galen"
#用于记录输入的次数
count = 0
while count<3:
print("第{}次输入".format(count+1))
username = input("username：")
#读取文件
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user_file.close()
#验证输入的用户是否已经被锁定
if username not in lock_user:
password = gp.getpass("password:")
if username == _username and password == _password:
print("Welocme {} come back".format(username))
count +=1
break
else:
print("you are illegal user")
count +=1
else:
#如果输入的用户被锁定，可以通过验证解除锁定
print("You have been locked,please contact with administrators")
#
if input("Are you want to contact administrators :") =="y":
if input("Please input your ide_code : ") =="Galen":
#输入输入验证码正确则，删除被锁用户名
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user.remove(username)
lock_user_file = open("lock_user.txt","wb")
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()
else:
print("You have lost the last chance")
break
#如果输入三次未登陆则锁定最后一次输入的用户
if count == 3 :
lock_user_file = open("lock_user.txt","rb")
lock_user = pickle.load(lock_user_file)
lock_user.append(username)
lock_user_file = open("lock_user.txt","wb")
pickle.dump(lock_user,lock_user_file)
lock_user_file.close()本文出自 “纯醪八盅VSIT” 博客，请务必保留此出处http://chunlaobazhong.blog.51cto.com/11499723/1956085
标签：python初学者
原文地址：http://chunlaobazhong.blog.51cto.com/11499723/1956085
