码迷,mamicode.com
首页 > 数据库 > 详细

SQL 笔记1,left join,group by,having

时间:2017-08-24 13:37:20      阅读:194      评论:0      收藏:0      [点我收藏+]

标签:order by   unknown   条件   分组   报错   desc   select   成绩   查询   

表:XS,XK,CJ

left join 表1 on 表1.字段=表2.字段

group by 分组条件

order by 排序条件 asc正序(小到大),desc倒序

having 跟条件类似where,不过需要在返回集字段中包含该字段

否则会报错:Unknown column ‘c.CJ‘ in ‘having clause‘,未知的列,在having

例:

#查询有不及格的成绩的学生姓名
SELECT 
s.XSMC, c.CJ
FROM cj c
LEFT JOIN xs s ON s.XSDM=c.XSDM
LEFT JOIN xk k ON k.XKDM=c.XKDM
GROUP BY c.XSDM 
HAVING c.CJ <60

 

 

#查询所有学生所有学科的成绩<=60
SELECT
s.XSMC,k.XKMC,c.CJ
FROM xs s,xk k,cj c
WHERE s.XSDM = c.XSDM
AND k.XKDM = c.XKDM
AND c.CJ <= 60


#查询学生总成绩
#ASC正序小到大,DESC倒序大到小
SELECT s.XSMC, SUM(c.CJ)
FROM xs s,xk k,cj c

WHERE s.XSDM = c.XSDM
AND k.XKDM = c.XKDM
GROUP BY c.XSDM
ORDER BY
SUM(c.CJ) ASC

 

SQL 笔记1,left join,group by,having

标签:order by   unknown   条件   分组   报错   desc   select   成绩   查询   

原文地址:http://www.cnblogs.com/tongs/p/7422400.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!