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创建Web项目运行时出小错误及解决方法

时间:2017-08-29 22:22:07      阅读:219      评论:0      收藏:0      [点我收藏+]

标签:http   目录结构   schema   结构   文件   html   项目   lang   nbsp   

1、目录结构

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2、各文件内容

index.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
  <head>
    <title>$Title$</title>
  </head>
  <body>
    <form action="/Servlet" method="post">
      <input type="submit" value="提交">
    </form>
  </body>
</html>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">
    <servlet>
        <servlet-name>Servlet</servlet-name>
        <servlet-class>web.servlet.Servlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>Servlet</servlet-name>
        <url-pattern>/Servlet</url-pattern>
    </servlet-mapping>
</web-app>

Servlet.java

package web.servlet;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

@WebServlet(name = "Servlet")
public class Servlet extends HttpServlet {
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("doPost()...");
    }
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("doGet()...");
    }
}

正常运行后运行后,Server控制台会出现输出“doPost()...”字符

3、当未配置web.xml时,出现的错误提示

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">
</web-app>

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解决方法:在web.xml中配置相关信息,或在Servlet.java注解中添加内容:

 @WebServlet(name = "Servlet",urlPatterns = "/Servlet") 

4、配置web.xml文件但未覆写doGet()和doPost()方法,或未覆写相对应的方法出现的错误提示

package web.servlet;

@WebServlet(name = "Servlet")
public class Servlet extends HttpServlet {
    
}
package web.servlet;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

@WebServlet(name = "Servlet")
public class Servlet extends HttpServlet {
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("doGet()...");
    }
}

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创建Web项目运行时出小错误及解决方法

标签:http   目录结构   schema   结构   文件   html   项目   lang   nbsp   

原文地址:http://www.cnblogs.com/gdwkong/p/7442697.html

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