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MySQL 分组后取每组前N条数据

时间:2017-08-31 21:04:46      阅读:292      评论:0      收藏:0      [点我收藏+]

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与oracle的 rownumber() over(partition by xxx  order by xxx )语句类似,即:对表分组后排序

创建测试emp表

DROP TABLE IF EXISTS emp;
CREATE TABLE emp (
  empno decimal(4,0) NOT NULL,
  ename varchar(10) DEFAULT NULL,
  job varchar(9) DEFAULT NULL,
  mgr decimal(4,0) DEFAULT NULL,
  hiredate datetime DEFAULT NULL,
  sal decimal(7,2) DEFAULT NULL,
  comm decimal(7,2) DEFAULT NULL,
  deptno decimal(2,0) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of emp
-- ----------------------------
INSERT INTO emp VALUES (‘7369‘, ‘SMITH‘, ‘CLERK‘, ‘7902‘, ‘1980-12-17 00:00:00‘, ‘800.00‘, null, ‘20‘);
INSERT INTO emp VALUES (‘7499‘, ‘ALLEN‘, ‘SALESMAN‘, ‘7698‘, ‘1981-02-20 00:00:00‘, ‘1600.00‘, ‘300.00‘, ‘30‘);
INSERT INTO emp VALUES (‘7521‘, ‘WARD‘, ‘SALESMAN‘, ‘7698‘, ‘1981-02-22 00:00:00‘, ‘1250.00‘, ‘500.00‘, ‘30‘);
INSERT INTO emp VALUES (‘7566‘, ‘JONES‘, ‘MANAGER‘, ‘7839‘, ‘1981-04-02 00:00:00‘, ‘2975.00‘, null, ‘20‘);
INSERT INTO emp VALUES (‘7654‘, ‘MARTIN‘, ‘SALESMAN‘, ‘7698‘, ‘1981-09-28 00:00:00‘, ‘1250.00‘, ‘1400.00‘, ‘30‘);
INSERT INTO emp VALUES (‘7698‘, ‘BLAKE‘, ‘MANAGER‘, ‘7839‘, ‘1981-05-01 00:00:00‘, ‘2850.00‘, null, ‘30‘);
INSERT INTO emp VALUES (‘7782‘, ‘CLARK‘, ‘MANAGER‘, ‘7839‘, ‘1981-06-09 00:00:00‘, ‘2450.00‘, null, ‘10‘);
INSERT INTO emp VALUES (‘7788‘, ‘SCOTT‘, ‘ANALYST‘, ‘7566‘, ‘1982-12-09 00:00:00‘, ‘3000.00‘, null, ‘20‘);
INSERT INTO emp VALUES (‘7839‘, ‘KING‘, ‘PRESIDENT‘, null, ‘1981-11-17 00:00:00‘, ‘5000.00‘, null, ‘10‘);
INSERT INTO emp VALUES (‘7844‘, ‘TURNER‘, ‘SALESMAN‘, ‘7698‘, ‘1981-09-08 00:00:00‘, ‘1500.00‘, ‘0.00‘, ‘30‘);
INSERT INTO emp VALUES (‘7876‘, ‘ADAMS‘, ‘CLERK‘, ‘7788‘, ‘1983-01-12 00:00:00‘, ‘1100.00‘, null, ‘20‘);
INSERT INTO emp VALUES (‘7900‘, ‘JAMES‘, ‘CLERK‘, ‘7698‘, ‘1981-12-03 00:00:00‘, ‘950.00‘, null, ‘30‘);
INSERT INTO emp VALUES (‘7902‘, ‘FORD‘, ‘ANALYST‘, ‘7566‘, ‘1981-12-03 00:00:00‘, ‘3000.00‘, null, ‘20‘);
INSERT INTO emp VALUES (‘7934‘, ‘MILLER‘, ‘CLERK‘, ‘7782‘, ‘1982-01-23 00:00:00‘, ‘1300.00‘, null, ‘10‘);

 

需求:按部门分组后显示工资为前三的员工信息

SQL:

select * from emp as a where 3> (select count(*) from emp where deptno = a.deptno and sal < a.sal  )  order by a.deptno ,a.sal

  

解析SQL:

3>...

目的是获取前三条数据,可以多次修改

emp where deptno = a.deptno

目的是确定分组字段

sal < a.sal

排序条件

 

结果图:

技术分享

 

  

MySQL 分组后取每组前N条数据

标签:创建   value   ima   显示   测试   sid   ted   .com   xxx   

原文地址:http://www.cnblogs.com/duyunchao-2261/p/7460294.html

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