标签:out efault cout 技术分享 else acm ret bool 题目
题目描述:


源码:
#include"iostream"
#include"string"
using namespace std;
bool IsFirstHalf(string *strs, int n, string str)
{
int count = 0;
for(int i = 0; i < n; i++)
{
if(str < strs[i])count++;
}
return count >= (n / 2 + n % 2);
}
int main()
{
int n, count[100], counts[5];
string **strs;
strs = new string*[5];
for(int i = 0; i < 5; i++)
{
strs[i] = new string[100];
}
while(cin>>n)
{
if(n < 0)break;
counts[1] = counts[2] = counts[3] = counts[4] = 0;
for(int i = 0; i < n; i++)
{
cin>>count[i]>>strs[0][i];
if(count[i] > 0 && count[i] < 5)
{
strs[count[i]][counts[count[i]]++] = strs[0][i];
}
}
for(int i = 0; i < n; i++)
{
switch(count[i])
{
case 5:
cout<<100<<endl;
break;
case 0:
cout<<50<<endl;
break;
default:
if(IsFirstHalf(strs[count[i]], counts[count[i]], strs[0][i]))
{
cout<<55 + 10 * count[i]<<endl;
}
else
{
cout<<50 + 10 * count[i]<<endl;
}
break;
}
}
cout<<endl;
}
return 0;
}
HD-ACM算法专攻系列(17)——find your present (2)
标签:out efault cout 技术分享 else acm ret bool 题目
原文地址:http://www.cnblogs.com/forcheng/p/7634892.html