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mysql left join中where和on条件的区别

时间:2017-10-18 12:35:55      阅读:170      评论:0      收藏:0      [点我收藏+]

标签:匹配   set   行记录   oca   mysq   基础上   join   不能   数据   

left join中关于where和on条件的几个知识点:
    1.多表left join是会生成一张临时表,并返回给用户
    2.where条件是针对最后生成的这张临时表进行过滤,过滤掉不符合where条件的记录,是真正的不符合就过滤掉。
    3.on条件是对left join的右表进行条件过滤,但依然返回左表的所有行,右表中没有的补为NULL
    4.on条件中如果有对左表的限制条件,无论条件真假,依然返回左表的所有行,但是会影响右表的匹配值。也就是说on中左表的限制条件只影响右表的匹配内容,不影响返回行数。
结论:
    1.where条件中对左表限制,不能放到on后面
    2.where条件中对右表限制,放到on后面,会有数据行数差异,比原来行数要多

测试:
创建两张表:
CREATE TABLE t1(id INT,name VARCHAR(20));
insert  into `t1`(`id`,`name`) values (1,‘a11‘);
insert  into `t1`(`id`,`name`) values (2,‘a22‘);
insert  into `t1`(`id`,`name`) values (3,‘a33‘);
insert  into `t1`(`id`,`name`) values (4,‘a44‘);

CREATE TABLE t2(id INT,local VARCHAR(20));
insert  into `t2`(`id`,`local`) values (1,‘beijing‘);
insert  into `t2`(`id`,`local`) values (2,‘shanghai‘);
insert  into `t2`(`id`,`local`) values (5,‘chongqing‘);
insert  into `t2`(`id`,`local`) values (6,‘tianjin‘);

测试01:返回左表所有行,右表符合on条件的原样匹配,不满足条件的补NULL
root@localhost:cuigl 11:04:25 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id;
+------+------+----------+
| id   | name | local    |
+------+------+----------+
|    1 | a11  | beijing  |
|    2 | a22  | shanghai |
|    3 | a33  | NULL     |
|    4 | a44  | NULL     |
+------+------+----------+
4 rows in set (0.00 sec)

测试02:on后面增加对右表的限制条件:t2.local=‘beijing‘
结论02:左表记录全部返回,右表筛选条件生效
root@localhost:cuigl 11:19:42 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id and t2.local=‘beijing‘;
+------+------+---------+
| id   | name | local   |
+------+------+---------+
|    1 | a11  | beijing |
|    2 | a22  | NULL    |
|    3 | a33  | NULL    |
|    4 | a44  | NULL    |
+------+------+---------+
4 rows in set (0.00 sec)

测试03:只在where后面增加对右表的限制条件:t2.local=‘beijing‘
结论03:针对右表,相同条件,在where后面是对最后的临时表进行记录筛选,行数可能会减少;在on后面是作为匹配条件进行筛选,筛选的是右表的内容。
root@localhost:cuigl 11:20:07 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id where t2.local=‘beijing‘;   
+------+------+---------+
| id   | name | local   |
+------+------+---------+
|    1 | a11  | beijing |
+------+------+---------+
1 row in set (0.01 sec)

测试04:t1.name=‘a11‘ 或者 t1.name=‘a33‘
结论04:on中对左表的限制条件,不影响返回的行数,只影响右表的匹配内容
root@localhost:cuigl 11:24:46 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id and t1.name=‘a11‘;  
+------+------+---------+
| id   | name | local   |
+------+------+---------+
|    1 | a11  | beijing |
|    2 | a22  | NULL    |
|    3 | a33  | NULL    |
|    4 | a44  | NULL    |
+------+------+---------+
4 rows in set (0.00 sec)
root@localhost:cuigl 11:25:04 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id and t1.name=‘a33‘;
+------+------+-------+
| id   | name | local |
+------+------+-------+
|    1 | a11  | NULL  |
|    2 | a22  | NULL  |
|    3 | a33  | NULL  |
|    4 | a44  | NULL  |
+------+------+-------+
4 rows in set (0.00 sec)

测试05:where t1.name=‘a33‘ 或者 where t1.name=‘a22‘
结论05:where条件是在最后临时表的基础上进行筛选,显示只符合最后where条件的行
root@localhost:cuigl 11:25:15 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id where t1.name=‘a33‘;   
+------+------+-------+
| id   | name | local |
+------+------+-------+
|    3 | a33  | NULL  |
+------+------+-------+
1 row in set (0.00 sec)
root@localhost:cuigl 11:27:27 >SELECT t1.id,t1.name,t2.local FROM t1 LEFT JOIN t2 ON t1.id=t2.id where t1.name=‘a22‘;
+------+------+----------+
| id   | name | local    |
+------+------+----------+
|    2 | a22  | shanghai |
+------+------+----------+
1 row in set (0.00 sec)

  

mysql left join中where和on条件的区别

标签:匹配   set   行记录   oca   mysq   基础上   join   不能   数据   

原文地址:http://www.cnblogs.com/cuisi/p/7685893.html

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