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Overlapping rectangles判断两个矩形是否重叠的问题 C++

时间:2017-10-21 21:58:11      阅读:379      评论:0      收藏:0      [点我收藏+]

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Given two rectangles, find if the given two rectangles overlap or not.

A rectangle is denoted by providing the x and y co-ordinates of two points: the left top corner and the right bottom corner of the rectangle.

Note that two rectangles sharing a side are considered overlapping.

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Input:

The first integer T denotes the number of test cases. For every test case, there are 2 lines of input. The first line consists of 4 integers: denoting the co-ordinates of the 2 points of the first rectangle. The first integer denotes the x co-ordinate and the second integer denotes the y co-ordinate of the left topmost corner of the first rectangle. The next two integers are the x and y co-ordinates of right bottom corner. Similarly, the second line denotes the cordinates of the two points of the second rectangle.


Output:

For each test case, output (either 1 or 0) denoting whether the 2 rectangles are overlapping. 1 denotes the rectangles overlap whereas 0 denotes the rectangles do not overlap.


Constraints:

1 <= T <= 10

-10000 <= x,y <= 10000

T denotes the number of test cases. x denotes the x co-ordinate and y denotes the y co-ordinate.


Example:

Input:
2
0 10 10 0
5 5 15 0
0 2 1 1
-2 -3 0 2

Output:
1
0

下面是我的代码实现:

 

Overlapping rectangles判断两个矩形是否重叠的问题 C++

标签:output   lines   ber   red   sts   otto   实现   bottom   sim   

原文地址:http://www.cnblogs.com/wongyi/p/7691426.html

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