标签:location cap returns before and operator [] static sig
A pointer to a const object of type T must also be const, of type const T*, meaning that the pointer may be assigned to but its contents may not. const double PI=3.1415926535898; double* p=&PI; // Error, would allow *p=4 to change PI const double* p=&PI; // OK, can‘t assign to *p (but may assign to p) double* const p=&PI; // Error, may assign to *p (but not to p) const double* const p=&PI; // OK, both *p and p are const /----------------------------------- A function name used without parenthesis(括号) is a pointer to a function. Function pointers can be assigned values and called. int f(double); // functions f and g take double and return int int g(double); int *h(double); // function h takes double and returns pointer to int int (*p)(double); // p is a pointer to a function that takes double and returns int int main() { p=f; p(3.0); // calls f(3.0) p=g; p(3.0); // calls g(3.0) p=h; // Error, type mismatch /--------------------------------- Explicit pointer conversions are allowed but usually unsafe. int i, *p=&i; i=int(3.0); // OK, rounds 3.0 *(double*)p = 3.0; // Crash, writes beyond end of i *(double*)&PI = 4; // Overwrites a const These may also be written (with the same results): i=static_cast<int>(3.0); // Apply standard conversions *reinterpret_cast<double*>p = 3.0; // Pretend p has type double* *const_cast<double*>&PI = 4; // Same type except for const /---------------------------------- The bare name of an array is a const pointer to the first element. If p is a pointer to an array element, then p+i points i elements ahead, to p[i]. By definition, p[i] is *(p+i). int a[5]; // a[0] through a[4] int* p=a+2; // *p is a[2] p[1]; // a[3] p-a; // 2 p>a; // true because p-a > 0 p-1 == a+1 // true, both are &a[1] *a; // a[0] or p[-2] a=p; // Error, a is const (but not *a) /-------------------------------------- A literal string enclosed in double quotes is an unnamed static array of const char with an implied ‘\0‘ as the last element. It may be used either to initialize an array of char, or in an expression as a pointer to the first char. Special chars in literals may be escaped with a backslash as before. Literal strings are concatenated without a + operator (convenient to span lines). char s[]="abc"; // char s[4]={‘a‘,‘b‘,‘c‘,‘\0‘}; const char* p="a" "b\n"; // Points to the ‘a‘ in the 4 element array "ab\n\0" const char* answers[2]={"no","yes"}; // Array of pointers to char cout << answers[1]; // prints yes (type const char*) cout << answers[1][0]; // prints y (type const char) "abc"[1] // ‘b‘ Arrays do not support copying, assignment, or comparison. int a[5], b[5]=a; // Error: can‘t initialize b this way b=a; // Error: can‘t assign arrays b==a; // false, comparing pointers, not contents "abc"=="abc" // false, comparing pointers to 2 different locations The size of an array created with new[] may be an expression. The elements cannot be initialized with a list. There is no run time check against accessing deleted elements. int n, *p; cin >> n; p=new int[n]; // Elements p[0] to p[n-1] with values initially undefined delete[] p; // Use delete with new or new(), delete[] with new[] p[0] = 1; // May crash /---------------------------------------- static objects are placed in the data segment. They are initialized from values stored in the executable file, and therefore these values must be known at compile time. Initialization occurs only once. Values are maintained when the object is out of scope (e.g. between function calls), and it is safe to return a pointer or reference to them. Numeric values not explicitly initialized are set to 0. int& f() { // Return by reference, f() is an alias for s, not a temporary copy static int s=1; // Initialized only once ++s; return s; // Safe to return by reference } int main() { cout << f(); // 2 cout << f(); // 3 f()=5; // OK, s=5; s=6; // Error, s is not in scope
标签:location cap returns before and operator [] static sig
原文地址:http://www.cnblogs.com/enyala/p/7780468.html