sql 消除重复

标签：维护   row   lis   from   次数   方法   max   判断   有用   

SELECT *
FROM tb_music_mp3
WHERE (songtype IN
(SELECT songtype
FROM tb_music_mp3
GROUP BY songtype
HAVING (COUNT(songtype) > 1)))

SELECT *
FROM tb_usertable_other_100000
WHERE (userid IN
(SELECT userid
FROM tb_usertable_other_100000
GROUP BY userid
HAVING (COUNT(userid) > 1)))

select *
FROM tb_usertable_main
WHERE (userid IN
(SELECT userid
FROM tb_usertable_main
GROUP BY userid
HAVING (COUNT(userid) > 1)))
order by userid

delete
FROM tb_usertable_other_5600000
WHERE (id NOT IN
(SELECT MIN(id)
FROM tb_usertable_other_5600000
GROUP BY userid))

在大的数据库应用中，经常因为各种原因遇到重复的记录，造成数据的冗余和维护上的不便。
id custom
1 化工公司
2 化工公司
3 化工公司
4 软件公司
5 制药公司
6 制药公司

现在想将重复的留下一条，重复的删除，结果如下：
id custom
1 化工公司
4 软件公司
5 制药公司

delete 表 where id not in(select min(id) from 表 group by custom)

SELECT *
FROM tb_music_mp3
WHERE (id NOT IN
(SELECT MIN(id)
FROM tb_music_mp3
GROUP BY songtype))

SELECT id, songtype, songname
FROM tb_music_mp3 a
WHERE (NOT EXISTS
(SELECT 1
FROM tb_music_mp3 b
WHERE a.songtype = b.songtype AND a.id > b.id))

1.用rowid方法

2.用group by方法

3.用distinct方法

1。用rowid方法

据据oracle带的rowid属性，进行判断，是否存在重复,语句如下：
查数据:
select * from table1 a where rowid !=(select max(rowid)
from table1 b where a.name1=b.name1 and a.name2=b.name2......)
删数据：
delete from table1 a where rowid !=(select max(rowid)
from table1 b where a.name1=b.name1 and a.name2=b.name2......)

2.group by方法

查数据:
　　select count(num), max(name) from student --列出重复的记录数，并列出他的name属性
　　group by num
　　having count(num) >1 --按num分组后找出表中num列重复，即出现次数大于一次
删数据：
　　delete c
　　这样的话就把所有重复的都删除了。

3.用distinct方法 -对于小的表比较有用

create table table_new as select distinct * from table1 minux
truncate table table1;
insert into table1 select * from table_new;

delete
FROM tb_book_list
WHERE (id NOT IN
(SELECT max(id)
FROM tb_book_list
GROUP BY bookid))
(5065 行受影响)

sql 消除重复

标签：维护   row   lis   from   次数   方法   max   判断   有用   

原文地址：http://www.cnblogs.com/lianruihong/p/7799530.html