标签:io os ar for 代码 on c amp line
k&r习题4-1,返回字符串t在s中最右边出现的位置,我写出了两种解决办法#include<stdio.h>
int strrindex(char s[], char t[])
{
int i,j,k,m,n;
m=strlen(s)-1;
n=strlen(t)-1;
for(i=m;i>0;i--){
for(j=i,k=n;k>0 && s[j]==t[k];j--,k--)
;
if(k==0)
return i-n;
}
return -1;
}
int strrindex2(char s[], char t[])
{
int i,j,k;
for(i=strlen(s)-strlen(t);i>=0;i--){
for(j=i,k=0;t[k]!=‘\0‘ && s[j]==t[k];j++,k++)
;
if(t[k]==‘\0‘ && k>0)
return i;
}
return -1;
}
/* compile with strrindex.c
*/
#include <stdio.h>
#define MAXLINE 100
int my_getline(char line[], int max);
int strrindex(char source[], char searchfor[]);
int strrindex2(char source[], char searchfor[]);
char pattern[]="stupid";
main()
{
char line[MAXLINE];
int pos=-1;
while(my_getline(line,MAXLINE)>0)
if((pos=strrindex(line,pattern))>=0){
printf("position is %d\n",pos);
}else
printf("not find\n");
return 0;
}
int my_getline(char s[], int lim)
{
int c, i;
for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != ‘\n‘;
++i)
s[i] = c;
if (c == ‘\n‘) {
s[i] = c;
++i;
}
s[i] = ‘\0‘;
return i;
}
标签:io os ar for 代码 on c amp line
原文地址:http://my.oschina.net/sukai/blog/313206