[leetcode]Gas Station @ Python

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原题地址：https://oj.leetcode.com/problems/gas-station/

题意：

There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station‘s index if you can travel around the circuit once, otherwise return -1.

Note:
The solution is guaranteed to be unique.

解题思路：这道题也很tricky，自己想是很难想出来的。如果sum(gas)<sum(cost)的话，那么一定无解。saving是走完一站邮箱剩下的油，如果加上gas[i]也到不了下一站，那么继续将下一站设置为起点，然后再检查，是不是很巧妙呢？

代码：时间复杂度O(n)，空间复杂度O(1)

class Solution:
    # @param gas, a list of integers
    # @param cost, a list of integers
    # @return an integer
    def canCompleteCircuit(self, gas, cost):
        if sum(gas) < sum(cost): return -1
        startIndex = 0
        saving = 0
        for i in range(len(gas)):
            if gas[i] + saving < cost[i]: 
                startIndex = i + 1
                saving = 0
            else:
                saving += gas[i] - cost[i]
        return startIndex

[leetcode]Gas Station @ Python

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原文地址：http://www.cnblogs.com/asrman/p/3970753.html