码迷,mamicode.com
首页 > 编程语言 > 详细

[leetcode]Candy @ Python

时间:2014-09-14 11:21:16      阅读:172      评论:0      收藏:0      [点我收藏+]

标签:style   blog   http   color   io   ar   strong   for   div   

原题地址:https://oj.leetcode.com/problems/candy/

题意:

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

解题思路:求最吝啬的糖果分发数。先从前到后扫描一遍数组,如果序列递增,就+1;然后从后到前扫描一遍数组,序列递增,+1。保证最低谷(ratings最小)永远是1就可以了。

代码: 时间复杂度O(n),空间复杂度O(n)

class Solution:
    # @param ratings, a list of integer
    # @return an integer
    def candy(self, ratings):
        candyNum = [1] * len(ratings)
        for i in range(1, len(ratings)):
            if ratings[i - 1] < ratings[i]:
                candyNum[i] = candyNum[i - 1] + 1
        for i in range(len(ratings) - 2, -1, -1):
            if ratings[i] > ratings[i + 1] and candyNum[i] <= candyNum[i + 1]:
                candyNum[i] = candyNum[i + 1] + 1
        return sum(candyNum)

 

[leetcode]Candy @ Python

标签:style   blog   http   color   io   ar   strong   for   div   

原文地址:http://www.cnblogs.com/asrman/p/3970780.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!