标签:show UI load control ase iat dep tty overflow
The landing page of my app has two states: home-public
, home-logged-in
. Now I want to show both states on the same URL, but let the controller and template depend on the user session (is the user logged in or not?).
Is there a way to achieve this?
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You could have a base state that controls which state to load, and you could simply have the child stated of that base state not have urls:
.state(‘home‘, {
url: "/home",
templateUrl: "....",
controller: function($scope,$state,authSvc) {
if(authSvc.userIsLoggedIn()){
$state.go(‘home.loggedin‘)
}else{
$state.go(‘home.public‘)
}
}
})
.state(‘home.public‘, {
url: "",
templateUrl: "....",
controller: function($scope) {
...........
}
})
.state(‘home.loggedin‘, {
url: "",
templateUrl: "....",
controller: function($scope) {
...........
}
})
Now in the controller of your base state (home
) you can check if the user is logged in or not, and use $state.go()
to load an appropriate state.
angular 的ui.router 定义不同的state 对应相同的url
标签:show UI load control ase iat dep tty overflow
原文地址:http://www.cnblogs.com/oxspirt/p/7995043.html