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银行家算法

时间:2017-12-13 02:06:26      阅读:199      评论:0      收藏:0      [点我收藏+]

标签:resources   最大值   iostream   scan   some   需要   param   界面   有一个   

自写的银行家算法 献丑献丑

#include<windows.h>
#include<iostream>
using namespace std;

int Max[5][3] = { { 7,5,3 },{ 3,2,2 },{ 9,0,2 },{ 2,2,2 },{ 4,3,3 } };
int Alloctation[5][3] = { { 0,1,0 },{ 2,0,0 },{ 3,0,2 },{ 2,1,1 },{ 0,0,2 } };
int Available[3] = { 3,3,2 };
int Need[5][3] = { { 7,4,3 },{ 1,2,2 },{ 6,0,0 },{ 0,1,1 },{ 4,3,1 } };//Need=Max-Alloctation

typedef struct _RESOURCES_
{

int Resource1;
int Resource2;
int Resource3;

}RESOURCES;

int v1 = 0;
int v2, v3, v4;
int v5[3] = { 0 };
DWORD WINAPI Procedure(LPVOID Parameter);
void SafeTest();
int main()
{
//界面
cout << "******************银行家算法**********************" << endl;
cout << " All Max Need" << endl;
cout << "P0 " << Alloctation[0][0] << Alloctation[0][1] << Alloctation[0][2] << " " << Max[0][0] << Max[0][1] << Max[0][2] << " " << Max[0][0] - Alloctation[0][0] << Max[0][1] - Alloctation[0][1] << Max[0][2] - Alloctation[0][2] << endl;
cout << "P1 " << Alloctation[1][0] << Alloctation[1][1] << Alloctation[1][2] << " " << Max[1][0] << Max[1][1] << Max[1][2] << " " << Max[1][0] - Alloctation[1][0] << Max[1][1] - Alloctation[1][1] << Max[1][2] - Alloctation[1][2] << endl;
cout << "P2 " << Alloctation[2][0] << Alloctation[2][1] << Alloctation[2][2] << " " << Max[2][0] << Max[2][1] << Max[2][2] << " " << Max[2][0] - Alloctation[2][0] << Max[2][1] - Alloctation[2][1] << Max[2][2] - Alloctation[2][2] << endl;
cout << "P3 " << Alloctation[3][0] << Alloctation[3][1] << Alloctation[3][2] << " " << Max[3][0] << Max[3][1] << Max[3][2] << " " << Max[3][0] - Alloctation[3][0] << Max[3][1] - Alloctation[3][1] << Max[3][2] - Alloctation[3][2] << endl;
cout << "P4 " << Alloctation[4][0] << Alloctation[4][1] << Alloctation[4][2] << " " << Max[4][0] << Max[4][1] << Max[4][2] << " " << Max[4][0] - Alloctation[4][0] << Max[4][1] - Alloctation[4][1] << Max[4][2] - Alloctation[4][2] << endl;
cout << "Avilable :" << Available[0] << " " << Available[1] << " " << Available[2] << endl;

while(true)
{
cout << "Input 0-4 Process to do someting" << endl;
//scanf("%d\r\n", &v1);
cin >> v1;
cout << endl;
if (v1 == 5)
{
SafeTest();

}

cout << "Intput three numbers that you want to write! " << endl;

cin >> v2 >> v3 >> v4;
v5[0] = v2, v5[1] = v3; v5[2] = v4;

HANDLE ThreadHandle0;
HANDLE ThreadHandle1;
HANDLE ThreadHandle2;
HANDLE ThreadHandle3;
HANDLE ThreadHandle4;

switch (v1)
{
case 0:
ThreadHandle0 = CreateThread(NULL, 0, Procedure, 0, 0, NULL);
CloseHandle(ThreadHandle0);
break;
case 1:
ThreadHandle1 = CreateThread(NULL, 0, Procedure, (LPVOID)v1, 0, NULL);
CloseHandle(ThreadHandle1);
break;
case 2:
ThreadHandle2 = CreateThread(NULL, 0, Procedure, (LPVOID)v1, 0, NULL);
CloseHandle(ThreadHandle2);
break;
case 3:
ThreadHandle3 = CreateThread(NULL, 0, Procedure, (LPVOID)v1, 0, NULL);
CloseHandle(ThreadHandle3);
break;
case 4:
ThreadHandle4 = CreateThread(NULL, 0, Procedure, (LPVOID)v1, 0, NULL);
CloseHandle(ThreadHandle4);
break;
}
Sleep(3000);
//printf("please input anykey to continue\r\n");
}
printf("please input anykey to exit\r\n");
getchar();
return 0;

 

}

DWORD WINAPI Procedure(LPVOID Parameter)
{
int i = 0;
i = (int)Parameter;
for (int j = 0; j<3; j++)
{
if (v5[j] <= Need[i][j])
{
if (v5[j]<=Available[j])
{
if (j == 0)
{
Available[j] = Available[j] - v2;
Alloctation[i][j] = Alloctation[i][j] + v2;
Need[i][j] = Need[i][j] - v2;
if (Available[j] < 0)
{
printf("请求资源大于可用资源\r\n");
}
printf("%d\r\n", Available[j]);
}
else if (j == 1)
{
Available[j] = Available[j] - v3;
Alloctation[i][j] = Alloctation[i][j] + v3;
Need[i][j] = Need[i][j] - v3;
if (Available[j] < 0)
{
printf("请求资源大于可用资源\r\n");
}
printf("%d\r\n", Available[j]);
}
else
{
Available[j] = Available[j] - v4;
Alloctation[i][j] = Alloctation[i][j] + v4;
Need[i][j] = Need[i][j] - v4;
if (Available[j] < 0)
{
printf("请求资源大于可用资源\r\n");
}
printf("%d\r\n", Available[j]);
SafeTest();

}

}
else
{
printf("尚且无足够的资源分配,需要等待!");
}
}
else
{
printf("所需要的资源数超过超过最大值\r\n");
}

}

return 0;
}

void SafeTest()
{
bool Finish[5] = { false };
int Need[5] = { 0 };
int j = 0;
int Count = 0; //计数

int Next = 0;
for (; j < 5; j++)
{
int m = 0; //计数器,用于下面计数三种资源有几个满足要求
if (Finish[j] == true)
{
continue;
}
else
{
for (int i = 0; i < 3; i++)
{
if ((Max[j][i] - Alloctation[j][i]) <= Available[i]) //需求的资源小于系统可用的资源数
{
m++;
}

}
if (m == 3)
{
Need[Next] = j; //记录进程号
Finish[j] = true; //释放该进程
for (int k = 0; k < 3; k++)
{
Available[k] += Alloctation[j][k]; //系统可用资源的回收
}
j = -1;
Next++; //记录数组下一次记录要从下一位开始
}

}

}


for (int i = 0; i < 5; i++)
{
if (Finish[i] == false)
{
cout << "不存在安全算法" << endl; //只要5个进程有一个没有通过而释放资源,说明当前系统不安全
}
else
{
Count++;
}
}
if (Count == 5) //如果q=5说明系统所以进程都释放了资源,系统安全
{
cout << "安全路径:";
for (int i = 0; i < 5; i++)
{
cout << "P" << Need[i] << " "; //一个一个释放记录数组中记录的进程号
}
cout << endl;
}

}

银行家算法

标签:resources   最大值   iostream   scan   some   需要   param   界面   有一个   

原文地址:http://www.cnblogs.com/L-Sunny/p/8030169.html

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