C#将Json解析成DateTable的方法

#region 将 Json 解析成 DateTable ///

/// 将 Json 解析成 DateTable。

/// Json 数据格式如: ///

{table:[{column1:1,column2:2,column3:3},{column1:1,column2:2,column3:3}]}

///

///要解析的 Json 字符串

/// 返回 DateTable public DataTable JsonToDataTable(string strJson)

{

//

取出表名 var rg = new Regex(@(?<={)[^:]+(?=:[), RegexOptions.IgnoreCase);

string strName = rg.Match(strJson).Value; DataTable tb = null;

// 去除表名 strJson = strJson.Substring(strJson.IndexOf([) + 1);

strJson = strJson.Substring(0, strJson.IndexOf(]));

// 获取数据

rg = new Regex(@(?<={)[^}]+(?=})); MatchCollection mc = rg.Matches(strJson);

for (int i = 0; i < mc.Count; i++) {

string strRow = mc[i].Value; string[] strRows = strRow.Split(‘,’);

// 创建表 if (tb == null) { tb = new DataTable();

tb.TableName = strName; foreach (string str in strRows)

{ var dc = new DataColumn();

string[] strCell = str.Split(‘:’);

dc.ColumnName = strCell[0].Replace(, );

tb.Columns.Add(dc); }

tb.AcceptChanges();

} // 增加内容 DataRow dr = tb.NewRow();

for (int j = 0; j < strRows.Length; j++)

{ dr[j] = strRows[j].Split(‘:’)[1].Replace(,

);

} tb.Rows.Add(dr);

tb.AcceptChanges();

}

return tb; }

#endregion

{

table: [

{

column1: 1,

column2: 2,

column3: 3

},

{

column1: 1,

column2: 2,

column3: 3

}

]

}

[{Code:MetaDataId,Name:MetaDataId},{Code:MetadataCode,Name:编号},{Code:SolutionName,Name:名称}]

[

{

Code: MetaDataId,

Name: MetaDataId

},

{

Code: MetadataCode,

Name: 编号

},

{

Code: SolutionName,

Name: 名称

}

]