本篇主要介绍了对一个N*N的数组，如果进行90度的旋转
首先，定义一个一维数组很简单，如下：
a = [i for i in range(10)] print(a) -----结果----- 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
此写法与下面的写法是相同的效果：
a = []
for i in range(10):
a.append(i)
print(a)
-----结果-----
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
那么二维数组应该如何进行创建呢，如下：
a = [[col for col in range(4)] for row in range(4)] #创建一个4*4的二维数组 print(a) -----结果---- [[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]
如果想要直观一些，稍微调整下：
a = [[col for col in range(4)] for row in range(4)]
for i in a:
print(i)
-----结果-----
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
接下来我们就要针对这个数组进行90度的旋转，把
[0, 1, 2, 3] [0, 1, 2, 3] [0, 1, 2, 3] [0, 1, 2, 3]
转换为：
[0, 0, 0, 0] [1, 1, 1, 1] [2, 2, 2, 2] [3, 3, 3, 3]
要实现该功能，我们先把步骤拆为3步：
第一步：
第二步：
第三步：
代码如下：
data = [[col for col in range(4)] for row in range(4)]
for row_index, row in enumerate(data):
for col_index in range(row_index, len(row)):
tmp = data[col_index][row_index] #设置一个临时变量
data[col_index][row_index] = row[col_index]
data[row_index][col_index] = tmp
print(‘‘) #防止打印结果看上去混乱，输入一个空内容
for r in data: #分步骤打印出转换结果
print(r)
-----结果-----
[0, 0, 0, 0]
[1, 1, 2, 3]
[2, 1, 2, 3]
[3, 1, 2, 3]
[0, 0, 0, 0]
[1, 1, 1, 1]
[2, 2, 2, 3]
[3, 3, 2, 3]
[0, 0, 0, 0]
[1, 1, 1, 1]
[2, 2, 2, 2]
[3, 3, 3, 3]
[0, 0, 0, 0]
[1, 1, 1, 1]
[2, 2, 2, 2]
[3, 3, 3, 3]
