SQL 基础--> 集合运算(UNION 与UNION ALL)
集合运算操作符可以将两个或多个查询返回的行组合起来，即集合属于纵向连接运算
一、常用的集合运算符
UNION ALL 返回各个查询检索出的所有的行，不过滤掉重复记录 UNION 返回各个查询检索出的过滤掉重复记录的所有行，即并集 INTERSECT 返回两个查询检索出的共有行，即交集 MINUS 返回将第二个查询检索出的行从第一个查询检索出的行中减去之后剩余的行，即差集
二、集合运算的原则
1.所有选择列表的表达式数目必须相同 2.对于结果集中各列，或个别子查询中的任意列的子集必须具有相同的数据类型，或是可以隐式转化为相同的数据类型，否则需显示转换 3.各个查询中对应的结果集列出现的顺序必须相同 4.生成的结果集中的列名来自UNION语句中第一个单独的查询
三、演示各个集合运算符
--为集合运算生成环境，生成有相同结构的emp表，且命名为emp2
idle> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
7369 SMITH CLERK 7902 1980-12-17 800 20
7499 ALLEN SALESMAN 7698 1981-02-20 1600 300 30
7521 WARD SALESMAN 7698 1981-02-22 1250 500 30
7566 JONES MANAGER 7839 1981-04-02 2975 20
7654 MARTIN SALESMAN 7698 1981-09-28 1250 1400 30
7698 BLAKE MANAGER 7839 1981-05-01 2850 30
7782 CLARK MANAGER 7839 1981-06-09 2450 10
7788 SCOTT ANALYST 7566 1987-04-19 3000 20
7839 KING PRESIDENT 1981-11-17 5000 10
7844 TURNER SALESMAN 7698 1981-09-08 1500 0 30
7876 ADAMS CLERK 7788 1987-05-23 1100 20
7900 JAMES CLERK 7698 1981-12-03 950 30
7902 FORD ANALYST 7566 1981-12-03 3000 20
7934 MILLER CLERK 7782 1982-01-23 1300 10
14 rows selected.
idle> create table emp2 tablespace tbs1 as select * from emp where empno in (7369,7654,7839,7876); Table created.
idle> insert into emp2 (empno,ename,sal) select 8001,‘ROBINSON‘,3500 from dual; 1 row created. idle> insert into emp2 (empno,ename,sal) select 8002,‘HENRY‘,3700 from dual; 1 row created. idle> insert into emp2 (empno,ename,sal) select 8004,‘JOHNSON‘,4000 from dual; 1 row created.
idle> select * from emp2;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
7369 SMITH CLERK 7902 1980-12-17 800 20
7654 MARTIN SALESMAN 7698 1981-09-28 1250 1400 30
7839 KING PRESIDENT 1981-11-17 5000 10
7876 ADAMS CLERK 7788 1987-05-23 1100 20
8001 ROBINSON 3500
8002 HENRY 3700
8004 JOHNSON 4000
7 rows selected.
--1.UNION 过滤了重复记录
idle> select empno,ename,job,hiredate,sal from emp
union
select empno,ename,job,hiredate,sal from emp2;
2 3
EMPNO ENAME JOB HIREDATE SAL
---------- ---------- --------- ---------- ----------
7369 SMITH CLERK 1980-12-17 800
7499 ALLEN SALESMAN 1981-02-20 1600
7521 WARD SALESMAN 1981-02-22 1250
7566 JONES MANAGER 1981-04-02 2975
7654 MARTIN SALESMAN 1981-09-28 1250
7698 BLAKE MANAGER 1981-05-01 2850
7782 CLARK MANAGER 1981-06-09 2450
7788 SCOTT ANALYST 1987-04-19 3000
7839 KING PRESIDENT 1981-11-17 5000
7844 TURNER SALESMAN 1981-09-08 1500
7876 ADAMS CLERK 1987-05-23 1100
7900 JAMES CLERK 1981-12-03 950
7902 FORD ANALYST 1981-12-03 3000
7934 MILLER CLERK 1982-01-23 1300
8001 ROBINSON 3500
8002 HENRY 3700
8004 JOHNSON 4000
17 rows selected.
--2.UNION ALL 并集，不去重复记录
idle> select empno,ename,job,hiredate,sal from emp
union all
select empno,ename,job,hiredate,sal from emp2;
2 3
EMPNO ENAME JOB HIREDATE SAL
---------- ---------- --------- ---------- ----------
7369 SMITH CLERK 1980-12-17 800
7499 ALLEN SALESMAN 1981-02-20 1600
7521 WARD SALESMAN 1981-02-22 1250
7566 JONES MANAGER 1981-04-02 2975
7654 MARTIN SALESMAN 1981-09-28 1250
7698 BLAKE MANAGER 1981-05-01 2850
7782 CLARK MANAGER 1981-06-09 2450
7788 SCOTT ANALYST 1987-04-19 3000
7839 KING PRESIDENT 1981-11-17 5000
7844 TURNER SALESMAN 1981-09-08 1500
7876 ADAMS CLERK 1987-05-23 1100
7900 JAMES CLERK 1981-12-03 950
7902 FORD ANALYST 1981-12-03 3000
7934 MILLER CLERK 1982-01-23 1300
7369 SMITH CLERK 1980-12-17 800
7654 MARTIN SALESMAN 1981-09-28 1250
7839 KING PRESIDENT 1981-11-17 5000
7876 ADAMS CLERK 1987-05-23 1100
8001 ROBINSON 3500
8002 HENRY 3700
8004 JOHNSON 4000
21 rows selected.
--3.INTERSECT 交集,返回两个结果集中共有了部分
idle> select empno,ename,job,hiredate,sal from emp
intersect
select empno,ename,job,hiredate,sal from emp2;
2 3
EMPNO ENAME JOB HIREDATE SAL
---------- ---------- --------- ---------- ----------
7369 SMITH CLERK 1980-12-17 800
7654 MARTIN SALESMAN 1981-09-28 1250
7839 KING PRESIDENT 1981-11-17 5000
7876 ADAMS CLERK 1987-05-23 1100
--4.MINUS 补集,前一个结果集减后一个结果集后的结果
idle> select empno as "EmployeeNo" ,ename "EmployeeName",job "Job" ,hiredate as "HireDate",sal "Sal" from emp
minus
select empno,ename,job,hiredate,sal from emp2
order by "Sal";
2 3 4
EmployeeNo EmployeeNa Job HireDate Sal
---------- ---------- --------- ---------- ----------
7900 JAMES CLERK 1981-12-03 950
7521 WARD SALESMAN 1981-02-22 1250
7934 MILLER CLERK 1982-01-23 1300
7844 TURNER SALESMAN 1981-09-08 1500
7499 ALLEN SALESMAN 1981-02-20 1600
7782 CLARK MANAGER 1981-06-09 2450
7698 BLAKE MANAGER 1981-05-01 2850
7566 JONES MANAGER 1981-04-02 2975
7788 SCOTT ANALYST 1987-04-19 3000
7902 FORD ANALYST 1981-12-03 3000
10 rows selected.
