SQL Server 中master..spt_values的应用

select number from master..spt_values with(nolock) where type=‘P‘
/**解释:master..spt_values表的字段值为P的对应number字段值是从0-2047*/ 
  
  
--1.将字符串转换为列显示 
  
if object_id(‘tb‘) is not null drop table tb 
go 
create table tb([编号] varchar(3),[产品] varchar(2),[数量] int,[单价] int,[金额] int,[序列号] varchar(8)) 
insert into tb([编号],[产品],[数量],[单价],[金额],[序列号]) 
select ‘001‘,‘AA‘,3,5,15,‘12,13,14‘ union all
select ‘002‘,‘BB‘,8,9,13,‘22,23,24‘
go 
select [编号],[产品],[数量],[单价],[金额] 
,substring([序列号],b.number,charindex(‘,‘,[序列号]+‘,‘,b.number)-b.number) as [序列号] 
from tb a with(nolock),master..spt_values b with(nolock) 
where b.number>=1 and b.number<len(a.[序列号]) and b.type=‘P‘
and substring(‘,‘+[序列号],number,1)=‘,‘
go 
drop table tb 
go 
/** 
编号   产品   数量          单价          金额          序列号 
---- ---- ----------- ----------- ----------- -------- 
001  AA   3           5           15          12 
001  AA   3           5           15          13 
001  AA   3           5           15          14 
002  BB   8           9           13          22 
002  BB   8           9           13          23 
002  BB   8           9           13          24 
*/ 
---------- 
  
--2.第四个逗号之前的字符串 
declare @str varchar(100) 
set @str=‘10,102,10254,103265,541,2154,41,156‘
;with cte as( 
select left(@str,number-1) as ss,row_number()over(order by getdate()) as xh 
from master..spt_values with(nolock)  
where number>=1 and number<=len(@str+‘,‘) and type=‘P‘ 
and substring(@str+‘,‘,number,1)=‘,‘
)select ss from cte where xh=4 
/** 
ss 
------------------- 
10,102,10254,103265 
*/ 
---------- 
  
  
--3.找出两句话中相同的汉字 
declare @Lctext1 varchar(100) 
declare @Lctext2 varchar(100) 
set @Lctext1=‘我们都是来自五湖四海的朋友‘
set @Lctext2=‘朋友多了路真的好走吗‘
select substring(@Lctext2,number,1) as value 
from master..spt_values with(nolock) 
where type=‘P‘ and number>=1 and number<=len(@Lctext2) 
and charindex(substring(@Lctext2,number,1),@Lctext1,number)>1 
/** 
value 
----- 
朋 
友 
的 
*/ 
--------- 
  
  
--4.提取两个日期之间的所有月份 
if object_id(‘tb‘) is not null drop table tb 
go 
create table tb(id int identity(1,1),startDate varchar(10),endDate varchar(10)) 
insert into tb(startDate,endDate) select ‘2013-01-01‘,‘2013-09-25‘
go 
declare @startDate varchar(10) 
declare @endDate varchar(10) 
select @startDate=startDate,@endDate=endDate from tb with(nolock) 
select convert(varchar(7),dateadd(mm,number,@startDate),120) as [月份] 
from master..spt_values with(nolock) 
where type=‘P‘ and number>=0 
and dateadd(mm,number,@startDate)<=@endDate 
go 
drop table tb 
go 
/** 
月份 
------- 
2013-01 
2013-02 
2013-03 
2013-04 
2013-05 
2013-06 
2013-07 
2013-08 
2013-09 
*/ 
--------- 
  
  
--5.求一个日期所在月份的所有日期 
declare @date datetime 
set @date=‘2013-08-31‘
select convert(char(7),@date,120)+‘-‘+right(‘0‘+convert(varchar(2),number),2) as [日期格式1] 
,ltrim(year(@date))+right(100+month(@date),2)+right(‘0‘+ltrim(number),2) as [日期格式2] 
from master..spt_values with(nolock) 
where type=‘P‘ and number>=1 
--and number<=datediff(dd,@date,dateadd(mm,1,@date)) --对于mssql而言该语句不试用于2013-08-31的情况，这时由于9月没有31号，固计算出来的天数是30天 
and number<=datediff(dd,convert(char(7),@date,120)+‘-01‘,convert(char(7),dateadd(mm,1,@date),120)+‘-01‘)--转换为1号来计算天数 
/** 
日期格式1       日期格式2 
----------- -------------------- 
2013-08-01  20130801 
2013-08-02  20130802 
2013-08-03  20130803 
2013-08-04  20130804 
2013-08-05  20130805 
2013-08-06  20130806 
2013-08-07  20130807 
2013-08-08  20130808 
2013-08-09  20130809 
2013-08-10  20130810 
2013-08-11  20130811 
2013-08-12  20130812 
2013-08-13  20130813 
2013-08-14  20130814 
2013-08-15  20130815 
2013-08-16  20130816 
2013-08-17  20130817 
2013-08-18  20130818 
2013-08-19  20130819 
2013-08-20  20130820 
2013-08-21  20130821 
2013-08-22  20130822 
2013-08-23  20130823 
2013-08-24  20130824 
2013-08-25  20130825 
2013-08-26  20130826 
2013-08-27  20130827 
2013-08-28  20130828 
2013-08-29  20130829 
2013-08-30  20130830 
2013-08-31  20130831 
*/ 
--------- 
  
  
--6.根据给定时间为基准以2小时为划分，得出一天划分出的时间段 
declare @time varchar(5) 
set @time=‘11:13‘
select ltrim(a.number)+right(@time,3)+‘-‘+ltrim(b.number)+right(@time,3) as [划分结果] 
from master..spt_values a with(nolock),master..spt_values b with(nolock) 
where a.type=‘P‘ and b.type=‘P‘
and a.number>=left(@time,2) and b.number<=24 
and a.number+2=b.number 
/** 
划分结果 
----------------------------------- 
11:13-13:13 
12:13-14:13 
13:13-15:13 
14:13-16:13 
15:13-17:13 
16:13-18:13 
17:13-19:13 
18:13-20:13 
19:13-21:13 
20:13-22:13 
21:13-23:13 
22:13-24:13 
*/ 
--------- 
  
  
--7.将字符串显示为行列 
if object_id(‘tb‘) is not null drop table tb 
create table tb(id int identity(1,1),s nvarchar(100)) 
insert into tb(s) select ‘车位地址1,车位状况1|车位地址2,车位状况2|车位地址n,车位状况n‘
;with cte as( 
select substring(s,number,charindex(‘|‘,s+‘|‘,number)-number) as ss 
from tb with(nolock),master..spt_values with(nolock) 
where type=‘P‘ and number>=1 and number<=len(s) 
and substring(‘|‘+s,number,1)=‘|‘
)select left(ss,charindex(‘,‘,ss)-1)as s1,substring(ss,charindex(‘,‘,ss)+1,len(ss))as s2 from cte 
drop table tb 
/** 
s1             s2 
----------- ------------ 
车位地址1      车位状况1 
车位地址2      车位状况2 
车位地址n      车位状况n 
*/