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Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
leetcode已经给出了二叉查找树的定义了。
class Solution: # @param root, a tree node # @return a boolean def isValidBST(self, root): if root is None: return True return self.helper(root,-99999,999999) # left ~ right 是node的取值范围 def helper(self,root,left,right): if root is None: return True if root.val <= left or root.val >=right: #超出范围 return False return self.helper(root.left,left,root.val) and self.helper(root.right,root.val,right)
找到画图工具后我再来更新部分的图
[leetcode] Validate Binary Search Tree (检验是否为二叉查找树) Python
标签:des style blog color io ar strong div sp
原文地址:http://www.cnblogs.com/zhidan/p/3978648.html