JAVA ZIP 处理文件

    public static void main(String[] args) throws IOException {
        String filePath = "E:\\技术部员工工作";
        ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream("E:\\技术部员工工作\\aaa.zip"));
        
        ZipEntry entry = new ZipEntry("dadsa.txt");
        byte[] d = FileUtils.readFileToByteArray(new File(filePath + "\\20140417.txt"));
        outputStream.putNextEntry(entry);
        outputStream.write(d);
        outputStream.closeEntry();
        //outputStream.closeEntry();
        ZipEntry entry1 = new ZipEntry("da1dsa.txt");
        byte[] d1 = FileUtils.readFileToByteArray(new File(filePath + "\\20140916.txt"));
        outputStream.putNextEntry(entry1);
        outputStream.write(d1);
        outputStream.closeEntry();
        
        outputStream.finish();
        outputStream.close();
    }