Sql Server字符串拆分(Split)方法汇总

--方法0：动态SQL法
declare @s varchar(100),@sql varchar(1000)
set @s=‘1,2,3,4,5,6,7,8,9,10‘
set @sql=‘select col=‘‘‘+ replace(@s,‘,‘,‘‘‘ union all select ‘‘‘)+‘‘‘‘
PRINT @sql
exec (@sql)

 
--方法1：循环截取法
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO

CREATE FUNCTION f_splitSTR(
@s   varchar(8000),   --待分拆的字符串
@split varchar(10)     --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
 DECLARE @splitlen int
 SET @splitlen=LEN(@split+‘a‘)-2
 WHILE CHARINDEX(@split,@s)>0
 BEGIN
  INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
  SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,‘‘)
 END
 INSERT @re VALUES(@s)
 RETURN
END
GO

 
--方法2：使用临时性分拆辅助表法
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO

CREATE FUNCTION f_splitSTR(
@s   varchar(8000),  --待分拆的字符串
@split varchar(10)     --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
 --创建分拆处理的辅助表(用户定义函数中只能操作表变量)
 DECLARE @t TABLE(ID int IDENTITY,b bit)
 INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b

 INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)
 FROM @t
 WHERE ID<=LEN(@s+‘a‘) 
  AND CHARINDEX(@split,@split+@s,ID)=ID
 RETURN
END
GO

 
--方法3：使用永久性分拆辅助表法
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[tb_splitSTR]‘) and objectproperty(id,N‘IsUserTable‘)=1)
drop table [dbo].[tb_splitSTR]
GO

--字符串分拆辅助表
SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR
FROM syscolumns a,syscolumns b
GO
--字符串分拆处理函数
CREATE FUNCTION f_splitSTR(
@s     varchar(8000),  --待分拆的字符串
@split  varchar(10)     --数据分隔符
)RETURNS TABLE
AS
RETURN(
 SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID) as varchar(100))
 FROM tb_splitSTR
 WHERE ID<=LEN(@s+‘a‘) 
  AND CHARINDEX(@split,@split+@s,ID)=ID)
GO



--方法4：循环字符串分割
create FUNCTION [dbo].[Fun_SplitStr]
(
    @originalStr      VARCHAR(8000), --要分割的字符串
    @split varchar(100)  --分隔符号
)
RETURNS @temp TABLE(Result VARCHAR(100))
AS
BEGIN
    DECLARE @result AS VARCHAR(100);   --定义变量用于接收单个结果 
    
     SET @originalStr = @originalStr + @split ;  
     
      
     WHILE (@originalStr <> ‘‘)
     BEGIN
         SET @result = LEFT(@originalStr, CHARINDEX(@split, @originalStr, 1) -1) ;  
         
         INSERT @temp VALUES(@result) ;  
         
         --STUFF()函数用于删除指定长度的字符，并可以在指定的起点处插入另一组字符。
         SET @originalStr = STUFF(@originalStr, 1, CHARINDEX(@split, @originalStr, 1), ‘‘);
     END 
     RETURN

END
 

--方法5：利用sql server2005的OUTER APPLY

CREATE FUNCTION [dbo].[ufn_SplitStringToTable]
(
  @str VARCHAR(MAX) ,
  @split VARCHAR(10)
)
RETURNS TABLE
    AS 
RETURN
    ( SELECT    B.id
      FROM      ( SELECT    [value] = CONVERT(XML , ‘<v>‘ + REPLACE(@str , @split , ‘</v><v>‘)
                            + ‘</v>‘)
                ) A
      OUTER APPLY ( SELECT  id = N.v.value(‘.‘ , ‘varchar(100)‘)
                    FROM    A.[value].nodes(‘/v‘) N ( v )
                  ) B
    )