-------下面使用标量值函数判断 出现重复的个数
create function fn_str_times
(
@str varchar(1000),--原子符串
@indexstr varchar(20)--查找的字符
)
returns int
as
begin
declare @findlen int
declare @times int
set @findlen=LEN(@indexstr)
set @times=0
while(charindex(@indexstr,@str))>0
BEGIN
set @str=SUBSTRING(@str,CHARINDEX(@indexstr,@str)+@findlen,len(@str))
set @times=@times+1
end
return @times
end
