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Luogu4175:[CTSC2008]网络管理Network

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标签:swap   down   ref   树状数组   +=   网络管理   tin   val   const   

题面

Luogu4175:[CTSC2008]网络管理Network

Sol

路径第\(k\)
无解直接判断就好了
然后整体二分,加上树链剖分+树状数组统计

# include <bits/stdc++.h>
# define RG register
# define IL inline
# define Fill(a, b) memset(a, b, sizeof(a))
using namespace std;
typedef long long ll;
const int _(2e5 + 5);

IL ll Input(){
    RG ll x = 0, z = 1; RG char c = getchar();
    for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    return x * z;
}

int size[_], fa[_], deep[_], top[_], son[_], dfn[_], Index;
int fst[_], nxt[_], to[_], cnt, n, c[_];

IL void Modify(RG int x, RG int v){
    for(; x <= n; x += x & -x) c[x] += v;
}

IL int Query(RG int x){
    RG int ret = 0;
    for(; x; x -= x & -x) ret += c[x];
    return ret;
}

IL void Add(RG int u, RG int v){
    nxt[cnt] = fst[u]; to[cnt] = v; fst[u] = cnt++;
}

IL void Dfs1(RG int u){
    size[u] = 1;
    for(RG int e = fst[u]; e != -1; e = nxt[e]){
        if(size[to[e]]) continue;
        fa[to[e]] = u; deep[to[e]] = deep[u] + 1;
        Dfs1(to[e]);
        size[u] += size[to[e]];
        if(size[to[e]] > size[son[u]]) son[u] = to[e];
    }
}

IL void Dfs2(RG int u, RG int Top){
    dfn[u] = ++Index; top[u] = Top;
    if(son[u]) Dfs2(son[u], Top);
    for(RG int e = fst[u]; e != -1; e = nxt[e])
        if(!dfn[to[e]]) Dfs2(to[e], to[e]);
}

IL int LCA(RG int u, RG int v){
    while(top[u] ^ top[v]){
        if(deep[top[u]] > deep[top[v]]) swap(u, v);
        v = fa[top[v]];
    }
    return deep[u] > deep[v] ? v : u;
}

IL int Calc(RG int u, RG int v){
    RG int ret = 0;
    while(top[u] ^ top[v]){
        if(deep[top[u]] > deep[top[v]]) swap(u, v);
        ret += Query(dfn[v]) - Query(dfn[top[v]] - 1);
        v = fa[top[v]];
    }
    if(deep[u] > deep[v]) swap(u, v);
    ret += Query(dfn[v]) - Query(dfn[u] - 1);
    return ret;
}

int m, tot, ans[_], Q, val[_];
struct Data{
    int id, x, y, k, op;
} q[_], q1[_], q2[_];

IL void Solve(RG int l, RG int r, RG int L, RG int R){
    if(L > R) return;
    if(l == r){
        for(RG int i = L; i <= R; ++i)
            if(q[i].id && ans[q[i].id] != -1) ans[q[i].id] = l;
        return;
    }
    RG int mid = (l + r) >> 1, t1 = 0, t2 = 0;
    for(RG int i = L; i <= R; ++i)
        if(q[i].id){
            RG int s = Calc(q[i].x, q[i].y);
            if(s >= q[i].k) q2[++t2] = q[i];
            else q[i].k -= s, q1[++t1] = q[i];
        }
        else{
            if(q[i].y > mid) q2[++t2] = q[i], Modify(dfn[q[i].x], q[i].op);
            else q1[++t1] = q[i];
        }
    for(RG int i = L; i <= R; ++i)
        if(!q[i].id && q[i].y > mid) Modify(dfn[q[i].x], -q[i].op);
    for(RG int i = L, j = 1; j <= t1; ++i, ++j) q[i] = q1[j];
    for(RG int i = L + t1, j = 1; j <= t2; ++i, ++j) q[i] = q2[j];
    Solve(l, mid, L, L + t1 - 1); Solve(mid + 1, r, L + t1, R);
}

int main(RG int argc, RG char* argv[]){
    tot = n = Input(); m = Input(); RG int mx = 0;
    for(RG int i = 1; i <= n; ++i){
        q[i].x = i, q[i].y = val[i] = Input(), q[i].op = 1;
        fst[i] = -1; mx = max(mx, val[i]);
    }
    for(RG int i = 1, x, y; i < n; ++i)
        x = Input(), y = Input(), Add(x, y), Add(y, x);
    Dfs1(1); Dfs2(1, 1);
    for(RG int i = 1; i <= m; ++i){
        RG int tk = Input(), tx = Input(), ty = Input();
        if(tk){
            RG int lca = LCA(tx, ty); ++Q;
            RG int len = deep[tx] + deep[ty] - 2 * deep[lca] + 1;
            if(tk > len) ans[Q] = -1;
            q[++tot] = (Data){Q, tx, ty, tk, 0};
        }
        else{
            q[++tot] = (Data){0, tx, val[tx], 0, -1};
            q[++tot] = (Data){0, tx, val[tx] = ty, 0, 1};
            mx = max(mx, ty);
        }
    }
    Solve(0, mx, 1, tot);
    for(RG int i = 1; i <= Q; ++i)
        if(ans[i] == -1) puts("invalid request!");
        else printf("%d\n", ans[i]);
    return 0;
}

Luogu4175:[CTSC2008]网络管理Network

标签:swap   down   ref   树状数组   +=   网络管理   tin   val   const   

原文地址:https://www.cnblogs.com/cjoieryl/p/8423587.html

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