int BIT[1000], a[1000], n; void update(int x, int val) { for(; x <= n; x += x&-x) BIT[x] += val; } int query(int x) { int sum = 0; for(; x > 0; x -= x&-x) sum += BIT[x]; return sum; } int main() { scanf(“%d”, &n); int i; for(i = 1; i <= n; i++) { scanf(“%d”, &a[i]); update(i, a[i]); } printf(“sum of first 10 elements is %d\n”, query(10)); printf(“sum of all elements in range [2, 7] is %d\n”, query(7) – query(2-1)); return 0; }
待解决类似问题: 历届试题 小朋友排队 http://lx.lanqiao.cn/problem.page?gpid=T123