码迷,mamicode.com
首页 > Web开发 > 详细

[LeetCode] 535. Encode and Decode TinyURL 编码和解码短URL

时间:2018-02-28 10:41:02      阅读:251      评论:0      收藏:0      [点我收藏+]

标签:can   int   where   sign   des   on()   ast   srand   zab   

Note: This is a companion problem to the System Design problem: Design TinyURL.
TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl and it returns a short URL such as http://tinyurl.com/4e9iAk.

Design the encode and decode methods for the TinyURL service. There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.

 

C++:

class Solution {
public:
    Solution() {
        dict = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
        short2long.clear();
        long2short.clear();
        srand(time(NULL));
    }

    // Encodes a URL to a shortened URL.
    string encode(string longUrl) {
        if (long2short.count(longUrl)) {
            return "http://tinyurl.com/" + long2short[longUrl];
        }
        int idx = 0;
        string randStr;
        for (int i = 0; i < 6; ++i) randStr.push_back(dict[rand() % 62]);
        while (short2long.count(randStr)) {
            randStr[idx] = dict[rand() % 62];
            idx = (idx + 1) % 5;
        }
        short2long[randStr] = longUrl;
        long2short[longUrl] = randStr;
        return "http://tinyurl.com/" + randStr;
    }

    // Decodes a shortened URL to its original URL.
    string decode(string shortUrl) {
        string randStr = shortUrl.substr(shortUrl.find_last_of("/") + 1);
        return short2long.count(randStr) ? short2long[randStr] : shortUrl;
    }
    
private:
    unordered_map<string, string> short2long, long2short;
    string dict;
};

  

[LeetCode] 535. Encode and Decode TinyURL 编码和解码短URL

标签:can   int   where   sign   des   on()   ast   srand   zab   

原文地址:https://www.cnblogs.com/lightwindy/p/8481759.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!