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python基础

时间:2018-03-01 21:48:11      阅读:235      评论:0      收藏:0      [点我收藏+]

标签:asi   nta   inter   lambda   color   log   面向对象   不能   集合   

容器

列表

技术分享图片
 1 # 容器
 2 li=[1,2,3,abc,4.5,[2,3,4],{1:one}]
 3 
 4 print(len(li))
 5 
 6 print(li[0])
 7 print(li[-1]) #{1:‘one‘}
 8 
 9 li=[1,2,3]
10 li.append(a)
11 li.append(b)
12 print(li)
13 li.append([4,5,6]) #[1, 2, 3, ‘a‘, ‘b‘, [4, 5, 6]]
14 print(li)
15 li=[1,2,3]
16 li.extend([4,5,6]) #[1, 2, 3, 4, 5, 6]
17 print(li)
18 
19 li=[1,2,3,4,5]
20 li.pop() #[1, 2, 3, 4]
21 print(li)
22 del(li[0])
23 del(li[1])
24 print(li)#[2, 4]
25 print(‘‘)
26 
27 li=[]
28 if not li:
29     print(empty)
30 else:
31     print(not empty)
32 print(‘‘)
View Code
技术分享图片
#遍历
li=[1,2,3]
for j in li:
    print(j)
for i in range(len(li)):
    print(li[i])
View Code

元组

#元组:不能写,只能读
t=(1,2,3)
print(t)

字典:key/value

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 1 d={a:1,2:b,c:3,4:d}
 2 print(len(d))
 3 
 4 d[a]=100
 5 d[4]=dd
 6 print(d)
 7 print(‘‘)
 8 
 9 #添加元素
10 d[e]=5
11 d[6]=f
12 print(d)
13 print(‘‘)
14 
15 #删除元素
16 d={a:1,2:b,c:3,4:d}
17 del(d[a])
18 del(d[2])
19 print(d)
20 print(‘‘)
21 
22 #判断key是否存在
23 d={a:1,2:b,c:3,4:d}
24 if a in d:
25     print(a in d)
26 if 2 in d:
27     print(2 in d)
28 if not (x in d):
29     print(x not in d)
30 print(‘‘)
31 
32 #判断字典是否为空
33 d={}
34 if not d:
35     print(d is empty)
36 print(‘‘)
37 
38 #遍历
39 d={a:1,2:b,c:3,4:d}
40 for k in d.keys():
41     print(str(k)+:+str(d[k]))
42 for k,v in d.items():
43     print(str(k)+":"+str(v))
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集合:没有重复元素

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 1 s_a=set([1,2,3,4,5])
 2 s_b=set([1,1,2,2,3,4,5]) #{1, 2, 3, 4, 5}
 3 print(s_a)
 4 print(s_b)
 5 print(‘‘)
 6 
 7 print(len(s_a))
 8 
 9 s_a.add(6)
10 s_a.add(6)
11 s_a.update([5,6,7,8,9]) #{1, 2, 3, 4, 5, 6, 7, 8, 9}
12 print(s_a)
13 print(‘‘)
14 
15 s_a.remove(8)
16 s_a.remove(9)
17 print(s_a)
18 print(‘‘)
19 
20 #判断元素是否存在
21 print(1 in s_a) #True
22 print(10 in s_a)
23 print(‘‘)
24 
25 #判断集合是否为空
26 s_a=set([])
27 if not s_a:
28     print(set is empty)
29 else:
30     print(set is not empty)
31 print(‘‘)
32 
33 #遍历
34 s_a=set([1,2,3,4,5])
35 for i in s_a:
36     print(i)
37 print(‘‘)
38 
39 #集合操作
40 s_a=set([1,2,3,4,5])
41 s_b=set([4,5,6,7,8])
42 #并集
43 print(s_a | s_b) #{1, 2, 3, 4, 5, 6, 7, 8}
44 print(s_a.union(s_b))
45 #交集 
46 print(s_a & s_b)#{4, 5}
47 print(s_a.intersection(s_b))
48 #差集
49 print(s_a - s_b) #{1, 2, 3}
50 print(s_a.difference(s_b))
51 #对称差
52 print(s_a ^ s_b) #{1, 2, 3, 6, 7, 8}
53 print((s_a | s_b)-(s_a&s_b))
54 print(s_a.symmetric_difference(s_b))
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字符串:不可变

技术分享图片
s=abcdefg
li=list(s)
li[4]=E
li[5]=F
print(li)
s=‘‘.join(li) #[‘a‘, ‘b‘, ‘c‘, ‘d‘, ‘E‘, ‘F‘, ‘g‘]
print(s)
print(‘‘)
View Code

切片:开区间[):<=  x <

技术分享图片
 1 li=[0,1,2,3,4,5,6,7,8,9,10]
 2 print(li[2:5]) #[2, 3, 4]
 3 print(li[:4]) #[0, 1, 2, 3]
 4 print(li[5:]) #[5, 6, 7, 8, 9, 10]
 5 print(li[:]) #[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
 6 print(li[0:6:2]) #[0, 2, 4]
 7 print(li[3::2]) #[3, 5, 7, 9]
 8 print(‘‘)
 9 
10 #负数索引和step
11 print(li[::-1]) #[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
12 print(li[::-2]) #[10, 8, 6, 4, 2, 0]
13 print(li[-6:-1:1])#[5, 6, 7, 8, 9]
14 print(li[-1::-1]) #[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
View Code

生成器:计算延迟,什么时候用到才计算这个值

面向对象

廖雪峰的教程

基础

技术分享图片
 1 class MyClass:
 2     def __init__(self,val):#初始化函数,不是构造函数
 3         self.val=val
 4 
 5     def display(self,s):
 6         print(%s:%d % (s,self.val))
 7 
 8 m=MyClass(100)
 9 print(m.val)
10 m.display(hello)
11 print(‘‘)
12 
13 m2=m
14 print(id(m)) #52343408
15 print(id(m2))#52343408
16 
17 fn=m.display
18 fn(hey)
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继承,多态

技术分享图片
 1 class Base:
 2     pass
 3 class MyClass(Base):
 4     def run(self):
 5         print(MyClass run)
 6 
 7 class MyClass2(Base):
 8     def run(self):
 9         print(MyClass2 run)
10 
11 m=MyClass()
12 print(isinstance(m,MyClass))
13 print(issubclass(MyClass2,Base))
14 print(‘‘)
15 
16 #多态
17 m2=MyClass2()
18 m.run()
19 m2.run()
20 
21 def duck(d):
22     d.run()
23 class Man:
24     def run(self):
25         print(man run)
26 
27 class Monkey:
28     def run(self):
29         print(monkey run)
30 
31 duck(Man())
32 duck(Monkey())
View Code

异常处理

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 1 import traceback
 2 
 3 try:
 4     print(try...)
 5     r=10/0
 6 except ZeroDivisionError as e:
 7     print(ZeroDivisionError:,e)
 8     print(traceback.print_exc())
 9 finally:
10     print(finally...)
11 
12 ‘‘‘
13 结果:
14 Traceback (most recent call last):
15 try...
16   File "D:/pythonproject/test/base/01container.py", line 5, in <module>
17     r=10/0
18 ZeroDivisionError: division by zero
19 ZeroDivisionError: division by zero
20 None
21 finally...
22 ‘‘‘
View Code

文件读写

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#字符读写
#二进制读写
import struct
with open(sample.bmp,rb) as f:
    header=struct.unpack(<2c6I2H,f.read(30))
    print(header)
View Code

json处理

技术分享图片
 1 import json
 2 
 3 d={ptyhon:100,c++:70,basix:60,others:{c:65,java:50}}
 4 jtxt=json.dumps(d) #字典转成json {"ptyhon": 100, "c++": 70, "basix": 60, "others": {"c": 65, "java": 50}}
 5 dd=json.loads(jtxt) #json转成字典  {‘ptyhon‘: 100, ‘c++‘: 70, ‘basix‘: 60, ‘others‘: {‘c‘: 65, ‘java‘: 50}}
 6 print(jtxt)
 7 print(dd)
 8 print(‘‘)
 9 
10 #非dict对象如何用json序列化?
11 class Student:
12     def __init__(self,name,age,score):
13         self.name=name
14         self.age=age
15         self.score=score
16 
17     def __str__(self):
18         return %s:%d,%d % (self.name,self.age,self.score)
19 
20 s=Student(Tome,15,85)
21 print(s)
22 print(s.__dict__) #{‘name‘: ‘Tome‘, ‘age‘: 15, ‘score‘: 85}
23 #方法1
24 jtxt=json.dumps(s,default=lambda obj:obj.__dict__)
25 print(jtxt) #{‘name‘: ‘Tome‘, ‘age‘: 15, ‘score‘: 85}
26 def d2s(d):
27     return Student(d[name],d[age],d[score])
28 print(json.loads(jtxt, object_hook =d2s)) #Tome:15,85
29 
30 #方法2
31 def s2d(s):
32     return s.__dict__
33 jtxt=json.dumps(s,default=s2d)
34 print(jtxt)
View Code

 

python基础

标签:asi   nta   inter   lambda   color   log   面向对象   不能   集合   

原文地址:https://www.cnblogs.com/com-on/p/8490094.html

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