Reverse Integer (JAVA)

 1 public class Solution {
 2     public int reverse(int x) {
 3         String str=x+"";
 4         boolean isNeg=false;
 5         if(str.charAt(0)==‘-‘)
 6         {
 7             str=str.substring(1);
 8             isNeg=true;
 9         }
10             
11         //System.out.println(str);
12         char temp=0;
13         char[] arr=new char[str.length()];
14         
15         for(int i=0;i<str.length();i++)
16         {
17             arr[i]=str.charAt(i);
18         }
19         //System.out.println(Arrays.toString(arr));
20         for(int i=0,j=arr.length-1;i<arr.length;i++,j--)
21         {
22             if(i<j)
23             {
24                 temp=arr[i];
25                 arr[i]=arr[j];
26                 arr[j]=temp;
27             }
28         }
29         //System.out.println(Arrays.toString(arr));
30         
31         //System.out.println(Integer.parseInt(String.valueOf(arr)));
32         return isNeg==false?Integer.parseInt(String.valueOf(arr)):-Integer.parseInt(String.valueOf(arr));
33     }
34 }

1 public int reverse(int x) {
2             int res=0;
3             while(x!=0)
4             {
5                 res=res*10+x%10;
6                 x/=10;
7             }
8             return res;
9         }