问题：输入出生日期和当前的日期，输出活了多少天
举例：你是昨天出生的，那么输出就为1
分三种情况讨论：
1、年份和月份都相同
2、年份相同月份不同，先计算出生当天是当年的第几天，后计算当前为当年的第几天，相减
3、年份不同，还是先计算出生当天为当年的第几天，后计算当前为当年的第几天，做闰年判断，逐一相加
闰年为一下两种情况
1、能被400整除
2、能被4整除但不能被100整除
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本题来自Udacity的计算机科学导论课程，用来做Python入门
Python语言兼具一般高级语言和脚本语言的特点，在官网下了一个东东，只会做脚本，函数现在只会一行一行往里敲，然后运行，无法调试，好像是需要找一个开发环境，有空弄
附代码
# By Websten from forums # # Given your birthday and the current date, calculate your age in days. # Account for leap days. # # Assume that the birthday and current date are correct dates (and no # time travel). # def is_leap(year): result = False if year % 400 == 0: result = True if year % 4 == 0 and year % 100 != 0: result = True return result def daysBetweenDates(year1, month1, day1, year2, month2, day2): daysOfMonths = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if year1 == year2 and month1 == month2: days = day2 - day1 if year1 == year2: days1 = 0 i = 0 while i < month1 - 1: days1 = days1 + daysOfMonths[i] i = i + 1 days1 = days1 + day1 if is_leap(year1) and month1 > 2: days1 = days1 + 1 days2 = 0 i = 0 while i < month2 - 1: days2 = days2 + daysOfMonths[i] i = i + 1 days2 = days2 + day2 if is_leap(year2) and month2 > 2: days2 = days2 + 1 days = days2 - days1 else: days1 = 0 i = 0 while i < month1 - 1: days1 = days1 + daysOfMonths[i] i = i + 1 days1 = days1 + day1 if is_leap(year1) and month1 > 2: days1 = days1 + 1 days2 = 0 i = 0 while i < month2 - 1: days2 = days2 + daysOfMonths[i] i = i + 1 days2 = days2 + day2 if is_leap(year2) and month2 > 2: days2 = days2 + 1 days = 365 - days1 + days2 if is_leap(year1): days = days + 1 year1 = year1 + 1 while year1 < year2: days = days + 365 year1 = year1 + 1 if is_leap(year1): days = days + 1 return days # Test routine def test(): test_cases = [((2012,1,1,2012,2,28), 58), ((2012,1,1,2012,3,1), 60), ((2011,6,30,2012,6,30), 366), ((2011,1,1,2012,8,8), 585 ), ((1900,1,1,1999,12,31), 36523)] for (args, answer) in test_cases: result = daysBetweenDates(*args) if result != answer: print "Test with data:", args, "failed" else: print "Test case passed!" test()
