1，判断值在元组中
>>> a = ( 1, 2, 3, 4, 10 ) >>> 10 in a True >>> ‘10‘ in a False
2，修改元组中的值，由于元组不能被直接修改，可以先把他转成列表，在通过列表修改之后，赋给一个新的元组对象
>>> a = ( 10, 20, 30, 40 ) >>> l = list( a ) >>> l[0] = 100 >>> t = tuple( l ) >>> t (100, 20, 30, 40) >>> id( a ) 139920488716168 >>> id( t ) 139920488447152 >>> type( a ) <type ‘tuple‘> >>> type( t ) <type ‘tuple‘> >>>
3，向集合添加一个值，删除一个值，求交集和并集
>>> a set([‘a‘, ‘c‘, ‘b‘, ‘e‘, ‘d‘, ‘g‘, ‘f‘]) >>> a.add( ‘ghostwu‘ ) >>> a set([‘a‘, ‘c‘, ‘b‘, ‘e‘, ‘d‘, ‘g‘, ‘f‘, ‘ghostwu‘]) >>> a.remove( ‘g‘ ) >>> a set([‘a‘, ‘c‘, ‘b‘, ‘e‘, ‘d‘, ‘f‘, ‘ghostwu‘]) >>> b = set( "abcdlmn" ) >>> a & b set([‘a‘, ‘c‘, ‘b‘, ‘d‘]) >>> a | b set([‘a‘, ‘c‘, ‘b‘, ‘e‘, ‘d‘, ‘f‘, ‘m‘, ‘l‘, ‘n‘, ‘ghostwu‘]) >>>
4，用字典实现一个学生成绩小系统，之后进行添加，修改，删除，排序等操作
>>> student = { ‘ghostwu‘ : { ‘name‘ : ‘ghostwu‘, ‘age‘ : 20, ‘score‘ : { ‘math‘ : 78, ‘english‘ : 66, ‘python‘ : 75 } } }
>>> student
{‘ghostwu‘: {‘age‘: 20, ‘score‘: {‘python‘: 75, ‘math‘: 78, ‘english‘: 66}, ‘name‘: ‘ghostwu‘}}
>>> student[‘tom‘] = { ‘name‘ : ‘tom‘, ‘age‘ : 21, ‘score‘ : { ‘math‘ : 60, ‘english‘ : 80, ‘python‘ : 90 } }
>>> student
{‘ghostwu‘: {‘age‘: 20, ‘score‘: {‘python‘: 75, ‘math‘: 78, ‘english‘: 66}, ‘name‘: ‘ghostwu‘}, ‘tom‘: {‘age‘: 21, ‘score‘: {‘python‘: 90, ‘math‘: 60, ‘english‘: 80}, ‘name‘: ‘tom‘}}
>>> student[‘ghostwu‘][‘score‘][‘php‘] = 90
>>> student[‘tom‘][‘score‘][‘php‘] = 50
>>> student[‘ghostwu‘][‘score‘][‘math‘] = 30
>>> del student[‘ghostwu‘][‘age‘]
>>> score1 = student[‘ghostwu‘][‘score‘].values()
>>> score1
[75, 90, 30, 66]
>>> score1.sort()
>>> score1
[30, 66, 75, 90]
>>> student.pop( ‘address‘, ‘shenzhen‘ )
‘shenzhen‘
>>> student
{‘ghostwu‘: {‘score‘: {‘python‘: 75, ‘php‘: 90, ‘math‘: 30, ‘english‘: 66}, ‘name‘: ‘ghostwu‘}, ‘tom‘: {‘age‘: 21, ‘score‘: {‘python‘: 90, ‘php‘: 50, ‘math‘: 60, ‘english‘: 80}, ‘name‘: ‘tom‘}}
>>>
