标签:open div mem turn 进制 getc space bsp hash
在写一发树状数组,个人理解为hash 一种,就是通过数字的二进制数字表示这个数字 应该计算多少
洛谷板子 水了两发
#include<bits/stdc++.h> using namespace std; #define LOACL freopen("in","r",stdin);\ freopen("out","w",stdout); const int inf = 987654321; const int sz = (int)1e6 + 5; #define CLR(arr,val) memset(arr,val,sizeof(arr)) #define DBG(x) cout<<(#x)<<"="<<x<<endl #define DBG2(x,y) cout<<(#x)<<"="<<x<<"\t"<<(#y)<<"="<<y<<endl #define DBG3(x,y,z) cout<<(#x)<<"="<<x<<"\t"<<(#y)<<"="<<y<<"\t"<<(#z)<<"="<<z<<endl #define FOR(i, a, b) for(int i=(a); i<(b); i++) #define REP(i, a, b) for(int i=(a); i<=(b); i++) #define DOWN(i, a, b) for(int i=(a); i>=(b); i--) #define low(x) (x)&(-x) int n,m,op,x,y,a[sz]; int read() { int x= 0; bool f = false; char c = getchar(); while(!isdigit(c) && c!=‘-‘) c=getchar(); if(c == ‘-‘) f=true, c=getchar(); while(isdigit(c)) { x= x*10+c-‘0‘; c=getchar(); } if(f) x=-x; return x; } void add(int x,int y) { while(x<=n) { a[x]+=y; x+=low(x); } } int getsum(int x ) { int sum =0; while(x) { sum+=a[x]; x-=low(x); } return sum; } int main() { LOACL n=read(),m=read(); REP(i,1,n) { add(i,read()); } // REP(i,1,n) DBG(a[i]); REP(i,1,m) { op =read(),x=read(),y=read(); if(op == 1) add(x,y); else cout<<getsum( y)-getsum(x-1)<<endl; } return 0; }
#include<bits/stdc++.h> using namespace std; #define LOACL freopen("in","r",stdin);\ freopen("out","w",stdout); const int inf = 987654321; const int sz = (int)1e6 + 5; #define CLR(arr,val) memset(arr,val,sizeof(arr)) #define DBG(x) cout<<(#x)<<"="<<x<<endl #define DBG2(x,y) cout<<(#x)<<"="<<x<<"\t"<<(#y)<<"="<<y<<endl #define DBG3(x,y,z) cout<<(#x)<<"="<<x<<"\t"<<(#y)<<"="<<y<<"\t"<<(#z)<<"="<<z<<endl #define FOR(i, a, b) for(int i=(a); i<(b); i++) #define REP(i, a, b) for(int i=(a); i<=(b); i++) #define DOWN(i, a, b) for(int i=(a); i>=(b); i--) #define low(x) (x)&(-x) int n,m,op,x,y,k,a[sz],t[sz<<1]; int read() { int x= 0; bool f = false; char c = getchar(); while(!isdigit(c) && c!=‘-‘) c=getchar(); if(c == ‘-‘) f=true, c=getchar(); while(isdigit(c)) { x= x*10+c-‘0‘; c=getchar(); } if(f) x=-x; return x; } void add(int x,int y) { while(x<=n) { t[x]+=y; x+=low(x); } } int getsum(int x ) { int sum =0; while(x) { sum+=t[x]; x-=low(x); } return sum; } int main() { LOACL n=read(),m=read(); // DBG2(n,m); REP(i,1,n) { a[i] = read(); add(i,a[i]-a[i-1]); } REP(i,1,m) { op =read() ; if(op == 1) { x=read(),y=read(),k=read(); add(y+1,-k); add(x,k); } else { x =read(); cout<<getsum(x)<<endl; } } return 0; }
标签:open div mem turn 进制 getc space bsp hash
原文地址:https://www.cnblogs.com/corx/p/8831589.html