shell函数递归调用实现目录的对比拷贝

 1 #!/bin/bash
 2 
 3 cpdifffile()
 4 {
 5 
 6     DIR1=$1
 7     DIR2=$2
 8     files1=`ls $DIR1`
 9     #files2=`ls $DIR2`
10     for file1 in $files1
11     do
12         ls $DIR2/$file1 > /dev/null 2>&1
13         if [ $? -eq 0 ]
14         then
15             echo $DIR2 have file $file1
16         else
17             echo will cp $DIR1/$file1 to $DIR2
18             cp -a $DIR1/$file1 $DIR2/
19         fi
20     done
21 }
22 
23 cpsamedir()
24 {
25     cpdifffile $1 $2
26     subdirs1=`ls -l $1 | grep "^d" | awk -F\  ‘{print $9}‘`
27     subdirs2=`ls -l $2 | grep "^d" | awk -F\  ‘{print $9}‘`
28     unset samedirs ##注意，此处要清空数组，否则上次调用的结果保存在这里将会形成环状，死循环
29     i=0
30     for subdir1 in $subdirs1
31     do
32         ls $2/$subdir1 > /dev/null 2>&1
33         if [ $? -eq 0 ]
34         then
35             samedirs[i]=$subdir1
36             let i++
37 
38         else
39             echo  $1 have dir $subdir1, but  $2 not.
40         fi
41     done
42     echo "bettenw $1 and $2, the same dir is:"
43     echo ${samedirs[@]}
44 
45     for samedir in ${samedirs[@]}
46     do
47         echo "now oparate $1/$samedir and $2/$samedir"
48         cpsamedir $1/$samedir $2/$samedir
49     done
50 
51 
52 
53 }
54 
55 main()
56 {
57     cpsamedir $1 $2
58 
59 }
60 
61 main $1 $2