标签:post tac ble code person 结果 odi sum stand
可独立使用(能实现自己编写测试类单独生成题目的功能)
可生成不同等级题目,类似于:
1级题目:2 + 5 = 、10 - 5 = 之类的两个数,一个运算符的题目
(2).题目运算(判题)
可独立使用,实现中缀表达式转为后缀表达式并计算;判断用户答题正误,并输出正确结果
可独立使用,实现分数算式的计算
可独立使用,实现对自动生成表达式的去重:如下若生成:2 + 5 = & 5 + 2 = 为同一题目
第一部分:生成题目
import java.util.Stack;
import java.util.Random;
import java.util.ArrayList;
import java.util.Scanner;
class Questions {
ArrayList<Object> array = new ArrayList<Object>();
Random generator = new Random();
char[] newchar = {'+', '-', '*', '/'};
protected int number;
int NUM;
public Questions() {
number = 0;
}
public Object getQuestion(int num) {
int num1 = num;
while (num > 0) {
int figure = (int) generator.nextInt(9) + 1;
array.add(figure);
number = (int) (Math.random() * 4);
array.add(newchar[number]);
num--;
}
String obj = "";
while (num < 2 * num1) {
obj += array.get(num);
num++;
}
int other = (int) generator.nextInt(9) + 1;
array.add(other);
obj += other + "=";
return obj;
}
}
第二部分:题目运算
//生成后缀表达式
public class Calculations {
public static void main(String[] args) {
Questions questions=new Questions();
Stack stack = new Stack();
Scanner Scan=new Scanner(System.in);
char c;
int count=0,answer;
char[] operation = new char[100];
String str = (String) questions.getQuestion(3);
System.out.println("请回答以下问题:\n"+str);
System.out.println("请输入你的答案:");
answer=Scan.nextInt();
for (int i = 0; i < str.length(); i++) {
c = str.charAt(i);
if (c >= '0' && c <= '9') {
operation[i] = c;
count++;
}
else {
if (c == '*' || c == '/') {
if (stack.empty()) {
stack.push((char) c);
} else if ((char) stack.peek() == '*' || (char) stack.peek() == '/') {
operation[i] = (char) stack.pop();
stack.push(c);
} else
stack.push(c);
} else if (c == '+' || c == '-') {
if (stack.empty()) {
stack.push(c);
} else if ((char) stack.peek() == '+' || (char) stack.peek() == '-') {
operation[i] = (char) stack.pop();
stack.push(c);
} else {
operation[i] = (char) stack.pop();
stack.push(c);
}
} else
stack.push(c);
}
}
int num = stack.size();
for (int a = 0; a < num; a++) {
operation[str.length() + a] = (char) stack.pop();
}
//后缀表达式计算
Stack<Integer> stack1 = new Stack<Integer>();
int m, n, sum,num1=str.length()+(str.length()-count);
for (int b = 0; b <= num1; b++) {
if (operation[b] >= '0' && operation[b] <= '9')
stack1.push((int) operation[b]-48);
else {
if (operation[b] == '+') {
m = stack1.pop();
n = stack1.pop();
sum = n + m;
stack1.push(sum);
} else if (operation[b] == '-') {
m = stack1.pop();
n = stack1.pop();
sum = n- m;
stack1.push(sum);
} else if (operation[b] == '*') {
m = stack1.pop();
n = stack1.pop();
sum = n * m;
stack1.push(sum);
} else if (operation[b] == '/') {
m = stack1.pop();
n = stack1.pop();
sum = n / m;
stack1.push(sum);
}
else if (operation[b] == ' ')
continue;
}
}
if ((int)stack1.peek()==answer)
System.out.println("恭喜你答对了!");
else
System.out.println("很遗憾,答错了!答案是:"+stack1.peek());
}
}
PSP2.1 | Personal Software Process Stages | 预估耗时(分钟) |
---|---|---|
Planning | 计划 | 60 |
Estimate | 估计这个任务需要多少时间 | 3 |
Development | 开发 2000 | 3000 |
Analysis | 需求分析 (包括学习新技术) | 350 |
Coding Standard | 代码规范 (为目前的开发制定合适的规范) | 60 |
Design UML | 设计项目UML类图 | 60 |
Coding | 具体编码 | 1500 |
Code Review | 代码复审 | 30 |
Test 测试 | (自我测试,修改代码,提交修改) | 300 |
Size Measurement 计算工作量(实际时间 ) | 2 | 2 |
Postmortem & Process Improvement Plan | 事后总结, 并提出过程改进计划 | 30 |
合计 | 4395 |
2017-2018-2 1723 『Java程序设计』课程 结对编程练习_四则运算
标签:post tac ble code person 结果 odi sum stand
原文地址:https://www.cnblogs.com/zhouyajie/p/8977718.html