数组循环

    let arr = [‘apple‘, ‘banana‘, ‘orange‘, ‘tomato‘];
     //循环内容
    for(let val of arr)
    {
        console.log(val);
    }
    //循环索引
    for(let index of arr.keys())
    {
        console.log(index);
    }
    //循环索引和索引所对应的值
    for(let item of arr.entries())
    {
        console.log(item);
    }
    for(let [key,val]  of arr.entries())
    {
        console.log(key,val);
    }

    //求数组的和/阶乘
    let arr = [1, 2, 3, 4,5];
    let b1 = arr.reduce((prev,val, index, arr2) => {
        return prev + val;
        //(prev是当前内容之前数的和)
    });
    console.log(b1);
    //b1=15

    //类似查找 数组里某一个元素符合条件，返回true
    let arr = [‘apple‘, ‘banana‘, ‘orange‘];
    let b = arr.some((val, index, arr) => {
        return val == "banana";
    });
    console.log(b);
    //数组里面所有额元素都要符合条件才返回true
    let arr2 = [‘1‘, ‘3‘, ‘5‘, ‘7‘];
    let b1 = arr2.every((val, index, arr2) => {
        return val % 2 == 1;
    });
    console.log(b1);

    //过滤一些不合格的“元素”；需要retrun
    //如果回调函数等于true就留下
    let arr = [
        { title: ‘aaa‘, read: 100, hot: true },
         { title: ‘bbb‘, read: 100, hot: false },
          { title: ‘ccc‘, read: 100, hot: true },
           { title: ‘ddd‘, read: 100, hot: false }
    ];
  let newarr=  arr.filter((val, index, arr) => {
      console.log(val, index, arr);
      return val.hot == true;
  })
  console.log(newarr);

    //非常有用  做数据交互“映射”正常情况下。
    //需要配合retrun, 返回一个新的数组,若是没tetrun相当于foreash
    //
    let arr = [
        { title: ‘aaa‘, read: 100, hot: true },
         { title: ‘aaa‘, read: 100, hot: true },
          { title: ‘aaa‘, read: 100, hot: true },
           { title: ‘aaa‘, read: 100, hot: true }
    ];
  let newarr=  arr.map((val, index, arr) => {
      console.log(val, index, arr);
      let json = {};
      json.t = `^_^${val.title}`;
      json.r = val.read+200;
      json.h = val.hot == true && ‘真棒！！！‘;
      return json;
  })
  console.log(newarr);