标签:def red example @param markdown line write div 经典的
Merge two sorted (ascending) linked lists and return it as a new sorted list. The new sorted list should be made by splicing together the nodes of the two lists and sorted in ascending order.
Given 1->3->8->11->15->null
, 2->null
, return 1->2->3->8->11->15->null
.
解题:很经典的一道题目,有序链表的合并。LintCode中链表默认没有头指针,不过此题可以构造一个带头结点的链表存放结果,最后返回的时候把头结点去掉即可。代码如下:
/**
* Definition for ListNode
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
/**
* @param l1: ListNode l1 is the head of the linked list
* @param l2: ListNode l2 is the head of the linked list
* @return: ListNode head of linked list
*/
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
// write your code here
ListNode nhead = new ListNode(0);
ListNode rear = nhead;
while(l1 != null && l2 != null){
if(l1.val < l2.val){
rear.next = l1;
l1 = l1.next;
}else{
rear.next = l2;
l2 = l2.next;
}
rear = rear.next;
rear.next = null;
}
if(l1 != null){
rear.next = l1;
}else{
rear.next = l2;
}
return nhead.next; //关键
}
}
165. Merge Two Sorted Lists【LintCode by java】
标签:def red example @param markdown line write div 经典的
原文地址:https://www.cnblogs.com/phdeblog/p/9125097.html