标签:lte 匿名函数 int nbsp 最大 返回值 调用 修改 计算机
# 上周复习 #迭代器 #生成器进阶 #内置函数 #55个 #带key方法的函数:max、min、filter、map、sorted #红色和黄色的方法为重点 #匿名函数 #lambda 参数1,参数二:返回值表达式 #和5个带key的内置函数可结合使用 #递归函数 #什么是递归:在函数中自己调用自己 #最大递归深度测试 #997 # n = 0 # def func(): # global n # n+=1 # print(n) # func() # func() # RecursionError: maximum recursion depth exceeded while calling a Python object # -->超出最大递归深度 #修改最大递归深度测试#3809 # import sys # sys.setrecursionlimit(100000) # n = 0 # def func(): # global n # n+=1 # print(n) # func() # func() # 1 金鑫 40 # 2 武sir 42 # 3 egon 44 # 4 alex 46 # def age(n): # if n == 1: # return 40 # else: # return age(n-1)+2 # # def age(4): # if 4 == 1: # return 40 # else: # return 46 # def age(3): # if 3 == 1: # return 40 # else: # return 44 # def age(2): # if 2 == 1: # return 40 # else: # return 42 # # print(age(4)) #三级菜单 # menu = { # ‘北京‘: { # ‘海淀‘: { # ‘五道口‘: { # ‘soho‘: {}, # ‘网易‘: {}, # ‘google‘: {} # }, # ‘中关村‘: { # ‘爱奇艺‘: {}, # ‘汽车之家‘: {}, # ‘youku‘: {}, # }, # ‘上地‘: { # ‘百度‘: {}, # }, # }, # ‘昌平‘: { # ‘沙河‘: { # ‘老男孩‘: {}, # ‘北航‘: {}, # }, # ‘天通苑‘: {}, # ‘回龙观‘: {}, # }, # ‘朝阳‘: {}, # ‘东城‘: {}, # }, # ‘上海‘: { # ‘闵行‘: { # "人民广场": { # ‘炸鸡店‘: {} # } # }, # ‘闸北‘: { # ‘火车战‘: { # ‘携程‘: {} # } # }, # ‘浦东‘: {}, # }, # ‘山东‘: {}, # } # # print(menu) #算法 #什么是算法:人脑复杂,计算机简单 #二分法基础版 # l = [2,3,5,10,15,16,18,22,26,30,32,35,41,42,43,55,56,66,67,69,72,76,82,83,88] # # def func(l,aim): # mid = (len(l))//2 # if l: # if aim > l[mid]: # func(l[mid+1:],aim) # elif aim < l[mid]: # func(l[:mid],aim) # elif aim == l[mid]: # print("bingo",mid) # else: # print(‘找不到‘) # func(l,66) #升级版 # l = [2,3,5,10,15,16,18,22,26,30,32,35,41,42,43,55,56,66,67,69,72,76,82,83,88] # def find(l,aim,start=0,end=None): # end =len(l) if end is None else end # mid_index = (end - start) //2 + start # if start<=end: # if l[mid_index]<aim: # return find(l,aim,start=mid_index+1,end=end) # elif l[mid_index]>aim: # return find(l, aim, start=start, end=mid_index-1) # else: # return mid_index # else: # return ‘找不到这个值‘ # ret=find(l,100) # print(ret) # 斐波那契 # 问第n个斐波那契数是多少 # 1,1,2,3,5,8,13 # def func(n): # if n==1 or n==2: # return 1 # else: # return func(n-1)+func(n-2) # ret = func(7) # print(ret) # 阶乘 # def func(n): # if n == 1: # return 1 # else: # return n*func(n-1) # # ret = func(5) # print(ret)
标签:lte 匿名函数 int nbsp 最大 返回值 调用 修改 计算机
原文地址:https://www.cnblogs.com/wujunjie-sir/p/9216931.html