SQL用了Union后的排序问题

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原文：https://blog.csdn.net/sinat_35861727/article/details/65628037

最近使用SQL语句进行UNION查询，惊奇的发现：SQL没问题，UNION查询也没问题，都可以得到想要的结果，可是在对结果进行排序的时候，却出问题了。

1.UNION查询没问题

1.  
   SELECT `id`,`username`,`mobile`,`time`,id AS leader
2.  
   FROM `grouporder_leader`
3.  
   WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
4.  
   UNION ALL
5.  
   SELECT leadorderid,username,mobile,time,null
6.  
   FROM `grouporder_partner`
7.  
   WHERE courseid=21 and status=1 and merchid=23

结果如下

2.排序就出问题了

1.  
   SELECT `id`,`username`,`mobile`,`time`,id AS leader
2.  
   FROM `grouporder_leader`
3.  
   WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
4.  
   ORDER BY time DESC
5.  
   UNION ALL
6.  
   SELECT leadorderid,username,mobile,time,null
7.  
   FROM `grouporder_partner`
8.  
   WHERE courseid=21 and status=1 and merchid=23
9.  
   ORDER BY time DESC

执行这条SQL语句之后就报错。

3.创建临时表

使用类似于创建临时表的方法保存查询结果，然后对临时表进行查询排序。

1.  
   SELECT id,username,mobile,time,leader
2.  
   FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
3.  
   FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
4.  
   UNION ALL
5.  
   SELECT leadorderid,username,mobile,time,null
6.  
   FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
7.  
   )
8.  
   ORDER BY time DESC

4.起别名

不知道为什么第3步中查询依旧没有，然后对UNION查询的结果起个别名，然后再查询排序就没问题了。

1.  
   SELECT a.id,a.username,a.mobile,a.time,a.leader
2.  
   FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
3.  
   FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
4.  
   UNION ALL
5.  
   SELECT leadorderid,username,mobile,time,null
6.  
   FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
7.  
   ) AS a
8.  
   ORDER BY time DESC

结果就正确了

查出来就好说了,再进行去重或者其他操作,也没问题.

1.  
   SELECT DISTINCT a.id,a.username,a.mobile,FROM_UNIXTIME(a.time,‘%Y/%m/%d‘) as _time,a.leader
2.  
   FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
3.  
   FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
4.  
   UNION ALL
5.  
   SELECT leadorderid,username,mobile,time,null
6.  
   FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
7.  
   ) AS a
8.  
   ORDER BY time DESC

9.  

SQL用了Union后的排序问题

标签：iter   details   https   nat   null   numbers   status   esc   class   

原文地址：https://www.cnblogs.com/tc310/p/9248217.html