标签:tor pause using class turn ace ring bsp div
思路:详见程序员面试指南
代码如下:
#include<iostream> #include<vector> #include<string> using namespace std; vector<int>getNextarray(string pat){ if (pat.size() == -1)return{ -1 }; vector<int>next(pat.size(), 0); next[0] = -1; next[1] = 0; int cn = 0; int pos = 2; while (pos < pat.size()){ if (pat[pos - 1] == pat[cn]){ next[pos++] == ++cn; } else if (cn>0){ cn = next[cn]; } else{ next[pos++] = 0; } } return next; } int getIndext(string str, string pattern){ if (str.size() == 0 || pattern.size() == 0 || str.size() < pattern.size())return -1; int si = 0; int pi = 0; vector<int>next = getNextarray(pattern); while (si < str.size() && pi < pattern.size()){ if (str[si] == pattern[pi]){ si++; pi++; } else if (next[pi] == -1){ si++; } else{ pi = next[pi]; } } return pi == pattern.size() ? si - pi : -1; } int main(){ string s1 = "aksabcafsabcafxdf"; string s2 = "abcafx"; int res = getIndext(s1, s2); cout << res << endl; system("pause"); return 0; }
标签:tor pause using class turn ace ring bsp div
原文地址:https://www.cnblogs.com/inception6-lxc/p/9314904.html