码迷,mamicode.com
首页 > 编程语言 > 详细

用Python实现简单的名片管理系统

时间:2018-07-20 14:38:16      阅读:294      评论:0      收藏:0      [点我收藏+]

标签:.com   app   ack   删除用户   ima   dea   phone   img   dict   

首先新建项目,包含主程序cards_main和工具库cards_tools:

如下:
技术分享图片
main函数主主要使用while和if实现4功能切换,切换的具体操作由cards_tools中的函数执行。不说了直接上代码,代码都比较简单:

(1)cards_main:

* coding : UTF-8 *

"""
File_name : cards_main.py
Author : jack
Date : 2018.7.18
Function : 名片管理系统主程序
"""
import cards_tools

使用while实现窗口的循环使用

while True:
?? cards_tools.cards_dis()
?? cards_input = input("请选择操作功能:")
?? if cards_input in ["1", "2", "3"]:
????? if cards_input == "1":
???????? print("- " 20)
???????? print("您选择输入的操作代码是: 1" )
???????? cards_tools.cards_add()
????? elif cards_input == "2":
???????? print("- "
20)
???????? print("您选择输入的操作代码是: 2" )
???????? cards_tools.cards_show_all()
????? elif cards_input == "3":
???????? print("- " 20)
???????? print("您选择输入的操作代码是: 3" )
???????? cards_tools.cards_requ()
?? elif cards_input == "0":
????? print("您选择输入的操作代码是: 0" )
????? print("即将退出系统......\n" "已退出系统,欢迎您下次【名片管理系统】!")
????? break
?? else:
????? cards_input = input("输入错误,请重新输入:")
????? cards_tools.cards_dis()
????? #cards_input = input("输入错误,请重新输入:")
????? while True:
???????? cards_input = input("输入错误,请重新输入:")
???????? cards_tools.cards_dis()
???????? if cards_input in ["1", "2", "3", "0"]:
??????????? if cards_input == "1":
?????????????? print("- "
20)
?????????????? print("您选择输入的操作代码是: 1")
?????????????? cards_tools.cards_add()
?????????????? break
??????????? if cards_input == "2":
?????????????? print("- " 20)
?????????????? print("您选择输入的操作代码是: 2")
?????????????? cards_tools.cards_show_all()
?????????????? break
??????????? if cards_input == "3":
?????????????? print("- "
20)
?????????????? print("您选择输入的操作代码是: 3")
?????????????? cards_tools.cards_requ()
?????????????? break
??????????? else:
??????????? # #print("返回主菜单")
?????????????? break
????? break
(2)cards_tools:

* coding : UTF-8 *

"""
File_name : cards_main.py
Author : jack
Date : 2018.7.18
Function : 名片管理系统tools
"""

显示菜单

def cards_dis():
?? """显示菜单"""
?? print(" " 20)
?? print("\t欢迎使用【名片管理系统 V1.0】\n"
????? "\t\t\t1. 新建名片\n" "\t\t\t2. 显示全部\n" "\t\t\t3. 查询名片\n\n" "\t\t\t0. 退出系统")
?? print(" " 20)
cards_list = []

新增名片

def cards_add ():
?? """新增名片"""
?? print("- " * 20 )
?? print("新增名片")
?? """输入-整理成字典-将字典存储到列表中-提示输入成功"""
?? name_str = input("请输入姓名:")
?? gender_str = input("请输入性别:")
?? tel_int = input("请输入电话:")
?? add_str = input("请输入地址:")
?? cards_dict = {"name" : name_str,
????????????? "gender" : gender_str,
????????????? "telephone" : tel_int,
????????????? "address" : add_str}
?? cards_list.append(cards_dict)
?? print(cards_list)
?? print("%s 的名片新增成功!" % name_str)

显示全部

def cards_show_all ():
?? """显示全部名片"""
?? print("- " 20)
?? print("显示所有名片")
?? if len(cards_list) == 0:
????? print("当前系统中没有名片,请新增名片!")
?? else:
????? print("="
40)
????? #print("姓名\t\t" "性别\t\t" "电话\t\t" "地址")
????? for name in ("姓名","性别","电话","地址"):
???????? print(name, end="\t\t")
????? print(" ")
????? for cards_dict in cards_list:
???????? print("%s\t\t%s\t\t%s\t\t%s" % (cards_dict["name"],
???????????????????????????????? cards_dict["gender"],
???????????????????????????????? cards_dict["telephone"],
???????????????????????????????? cards_dict["address"]))
???????? print(cards_dict)
????? print("=" * 40)

查询名片

def cards_requ ():
?? """查询名片"""
?? print("- " 20)
?? print("查询名片")
?? find_name = input("请输入要搜索的姓名:")
?? if len(cards_list) == 0:
????? print("抱歉!没找到用户 %s 的信息, 请新增!" % find_name)
?? else:
????? for search_name in cards_list:
???????? if search_name["name"] == find_name:
??????????? print("找到 %s 的信息了。" % find_name)
??????????? print("="
40)
??????????? for name in ("姓名", "性别", "电话", "地址"):
?????????????? print(name, end="\t\t")
??????????? print(" ")
??????????? print("s%\t\ts%\t\ts%\t\ts%" % (search_name["name"],
??????????????????????????????????? search_name["gender"],
??????????????????????????????????? search_name["telephone"],
??????????????????????????????????? search_name["address"]))
??????????? print("=" * 40)
??????????? cards_deal(search_name)
??????????? break
???????? else:
??????????? print("抱歉!没找到用户 %s 的信息。" % find_name)

删除和修改名片信息

def cards_deal(find_dict):
?? """修改和删除名片"""
?? deal_cards = input("请选择要进行的操作: [1] 删除\t\t[2] 修改\t\t[3] 返回主菜单\n")
?? if deal_cards in ["1","2","3"]:
????? if deal_cards == "1":
???????? cards_list.remove(find_dict)
???????? print("删除用户 %s 名片成功!" % (find_dict["name"]))
????? if deal_cards == "2":
???????? find_dict["name"] = cards_mod(find_dict["name"], "请输入修改后的姓名:")
???????? find_dict["gender"] = cards_mod(find_dict["gender"], "请输入修改后的性别:")
???????? find_dict["telephone"] = cards_mod(find_dict["telephone"], "请输入修改后的电话:")
???????? find_dict["address"] = cards_mod(find_dict["address"], "请输入修改后的地址:")
???????? print("用户 %s 的名片修改成功!" % find_dict["name"])
?? else:
???????? print("输入错误,请重新输入!")
def cards_mod(cards_value, cards_new):
?? result = input(cards_new)
?? if len(result) > 0:
????? return result
?? else:
????? return cards_value
本人也是新手,欢迎大佬们批评指正。

用Python实现简单的名片管理系统

标签:.com   app   ack   删除用户   ima   dea   phone   img   dict   

原文地址:http://blog.51cto.com/9959014/2147638

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!