标签:lag 除法 color 类型 逆序输出 inpu 取整 size float
1 ‘‘‘
2 二进制->十进制:bTod
3 整数部分:a乘以2的n次方(n:a后面的整数位数)
4 小数部分:a乘以2的-n次方(n:a是小数点后几位)
5 十进制->二进制dTob
6 整数部分:短除法(除二取余法,逆序输出)
7 小数部分:乘二取整法,0.……正向输出所得
8
9 函数中形参n为字符串类型
10 ‘‘‘
11 #二进制->十进制
12 def bTod(n, pre = 4):
13 s_int = n
14 s_float = ‘‘
15 total_int, total_float = 0, 0
16 if ‘.‘ in n:
17 s_int, s_float = n.split(‘.‘)
18
19 li = len(s_int)
20 for c in s_int:
21 li = li - 1
22 total_int = total_int + int(c)*pow(2,li)
23
24 lf = 0
25 for c in s_float:
26 lf = lf + 1
27 total_float = total_float +int(c)*pow(2,-lf)
28
29 print("{}转化为十进制是{:.{}f}".format(n,total_int + total_float, pre))
30
31 #十进制->二进制
32 def dTob(n, pre = 4):
33 num_int = int(eval(n))
34 num_float = eval(n) - num_int
35 t_int, t_float = ‘‘, ‘‘
36 if ‘.‘ in n:
37 s_int, s_float = n.split(‘.‘)
38
39 while num_int!= 0:
40 a = num_int % 2
41 t_int = t_int + str(a)
42 num_int = num_int//2
43
44 while num_float != 0:
45 b = num_float*2
46 t_float = t_float + str(int(b))
47 num_float = b - int(b)
48
49 #print(t_int[::-1] + ‘.‘ + t_float[:])
50 print("{}转化为二进制是{:.{}f}".format(n,eval(t_int[::-1] + ‘.‘ + t_float[:]), pre))
51
52
53 a = input("请输入0(转化为十进制)或输入1(转化为二进制):")
54 if a == ‘0‘:
55 while True:
56 n = input("请输入一个二进制数:")
57 flag = 1
58 for c in n:
59 if c != ‘1‘ and c != ‘0‘:
60 print("输入错误,请重新输入")
61 flag = 0
62 break
63 if flag:
64 break
65 pre = int(input("请输入保留几位小数:"))
66 bTod(n,pre)
67 elif a == ‘1‘:
68 while True:
69 n = input("请输入一个十进制数:")
70 flag = 1
71 for c in n:
72 if c <= ‘0‘ or c >= ‘9‘:
73 print("输入错误,请重新输入")
74 flag = 0
75 break
76 if flag:
77 break
78 pre = int(input("请输入保留几位小数:"))
79 dTob(n,pre)
80 else:
81 print("无效输入")
标签:lag 除法 color 类型 逆序输出 inpu 取整 size float
原文地址:https://www.cnblogs.com/zcl843264327/p/9348199.html