leetcode169 python3 92ms 求众数

标签：lse   python3   def   turn   sel   python   element   not   etc   

class Solution:
    def majorityElement(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        freq = {}
        for i in nums:
            if i not in freq.keys():
                freq[i] = 1
            else:
                freq[i] += 1
            if freq[i] > len(nums)//2:
                return i
        

leetcode169 python3 92ms 求众数

标签：lse   python3   def   turn   sel   python   element   not   etc   

原文地址：https://www.cnblogs.com/theodoric008/p/9420376.html