通过身份证分析出生年月日、性别、年龄的SQL语句

update [表名] set [性别]=(case when (left(right([身份证],2),1) % 2 = 0) then ‘女‘ else ‘男‘ end ) where len([身份证])=18 and left(right([身份证],2),1)<>‘X‘
update [表名] set [性别]=(case when (right([身份证],1) % 2 = 0) then ‘女‘ else ‘男‘ end ) where len([身份证])=15 and right([身份证],1)<>‘X‘
update [表名] set [出生日期]=(right(left([身份证],10),4)+‘-‘+right(left([身份证],12),2)+‘-‘+right(left([身份证],14),2)) where len([身份证])=18
update [表名] set [出生日期]=(‘19‘+right(left([身份证],8),2)+‘-‘+right(left([身份证],10),2)+‘-‘+right(left([身份证],12),2)) where len([身份证])=15
update [表名] set [年龄]=year(getdate())-(cast(left([出生日期],4) as int)) where [出生日期]<>‘‘

#字符串格式化为日期格式
SELECT DATE_FORMAT(‘19841201‘,‘%Y-%m-%d‘)
 
#---知道出生日期求年龄
SELECT TIMESTAMPDIFF(YEAR,DATE_FORMAT(‘19841201‘,‘%Y-%m-%d‘),CURDATE());
 
#截取身份证号中的年月日
SELECT SUBSTR(‘152824197810116015‘,7,8);
SELECT SUBSTR(‘152824781011601‘,7,6)
 
#连接字符串
SELECT CONCAT(‘33‘,‘22‘)
 
#截取身份证号中的年月日 1
SELECT  IF (LENGTH(‘152824197810116015‘)=18,
            SUBSTR(‘152824197810116015‘,7,8),
             CONCAT(‘19‘,SUBSTR(‘152824197810116015‘,7,6))
                    );
#截取身份证号中的年月日 2
SELECT  IF (LENGTH(‘152824781011601‘)=18,
            SUBSTR(‘152824781011601‘,7,8),
             CONCAT(‘19‘,SUBSTR(‘152824781011601‘,7,6))
                    );
#根据身份证号计算年龄
SELECT TIMESTAMPDIFF(YEAR,
     DATE_FORMAT( IF (LENGTH(‘152824781011601‘)=18,
            SUBSTR(‘152824781011601‘,7,8),
             CONCAT(‘19‘,SUBSTR(‘152824781011601‘,7,6))
                    ),‘%Y-%m-%d‘),
     CURDATE());

update @T
set nl = case when len(ltrim(rtrim(sfz))) = 18 then cast(Year(GetDate()) as int)- cast(substring(ltrim(rtrim(sfz)),7,4) as int)
  else cast(Year(GetDate()) as int)- cast(‘19‘+substring(ltrim(rtrim(sfz)),7,2) as int) end