Sql同一列中两条数据时间差计算

IF OBJECT_ID(‘tempdb..#logs‘,‘U‘)is NOT NULL DROP TABLE #logs
IF OBJECT_ID(‘tempdb..#logs2‘,‘U‘)is NOT NULL DROP TABLE #logs2
IF OBJECT_ID(‘tempdb..#logs3‘,‘U‘)is NOT NULL DROP TABLE #logs3

CREATE TABLE #logs(
    ODate DATETIME
    ,Operation VARCHAR(20)
    ,ID INT
);
INSERT INTO #logs VALUES(‘2018-08-09 09:00:00‘,‘提交需求‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 10:00:00‘,‘驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 11:30:00‘,‘撤销驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 12:00:00‘,‘驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 13:10:00‘,‘撤销驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 13:50:00‘,‘驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 19:00:00‘,‘撤销驳回‘,1);
INSERT INTO #logs VALUES(‘2018-08-09 22:00:00‘,‘通过‘,1);

INSERT INTO #logs VALUES(‘2018-08-10 09:00:00‘,‘提交需求‘,2);
INSERT INTO #logs VALUES(‘2018-08-10 10:00:00‘,‘驳回‘,2);
INSERT INTO #logs VALUES(‘2018-08-11 11:30:00‘,‘撤销驳回‘,2);
INSERT INTO #logs VALUES(‘2018-08-11 12:00:00‘,‘驳回‘,2);
INSERT INTO #logs VALUES(‘2018-08-11 13:00:00‘,‘撤销驳回‘,2);
INSERT INTO #logs VALUES(‘2018-08-11 22:00:00‘,‘通过‘,2);

--对时间进行排序并编号
SELECT ID,ODate,Operation,ROW_NUMBER() OVER (PARTITION BY id ORDER BY ODate)RowNum 
INTO #logs2 
FROM #logs

--新增列：下一步操作的时间
SELECT ID,Operation,ODate AS ADate ,
(
    SELECT ODate FROM #logs2 WHERE rownum=t.rownum+1 and ID=t.id
)AS BDate
INTO #logs3 
FROM #logs2 t

--计算需求提出到通过耗时（剔除驳回到撤销驳回耗时）
SELECT ID,SUM(DATEDIFF(MI,ADate,Bdate)) CostTime FROM #logs3
WHERE Operation<>‘驳回‘
GROUP BY ID