码迷,mamicode.com
首页 > 编程语言 > 详细

python 验证码识别示例(二) 复杂验证码识别

时间:2018-08-10 19:42:24      阅读:418      评论:0      收藏:0      [点我收藏+]

标签:nal   filename   折线   dump   大小   int   path   训练   with   

   在这篇博文中手把手教你如何去分割验证,然后进行识别。

一:下载验证码

    技术分享图片

  验证码分析,图片上有折线,验证码有数字,有英文字母大小写,分类的时候需要更多的样本,验证码的字母是彩色的,图片上有雪花等噪点,因此识别改验证码难度较大

 

二:二值化和降噪:

  技术分享图片

 

 

 三: 切割:

    技术分享图片

 

 四:分类:

    技术分享图片

 

 

五:   测试识别率

  技术分享图片   技术分享图片     技术分享图片   技术分享图片   技术分享图片

 

 六:总结:

  综合识别率在70%左右,对于这个识别率我觉得还是挺高的,因为这个验证码的识别难度还是很大

代码:

1.  下载图片:

  

#-*-coding:utf-8-*-
import requests

def spider():
    url = "https://www.epailive.com/basic/captcha?ran=0.22070346581876787"
    for i in range(1, 101):
        print("正在下载的张数是:",i)
        with open("./1__get_image/{}.png".format(i), "wb") as f:
            f.write(requests.get(url).content)
spider()

二值化和降噪:

  

#-*-coding:utf-8-*-
# coding:utf-8
import sys, os
from PIL import Image, ImageDraw

# 二值数组
t2val = {}


def twoValue(image, G):
    for y in range(0, image.size[1]):
        for x in range(0, image.size[0]):
            g = image.getpixel((x, y))
            if g > G:
                t2val[(x, y)] = 1
            else:
                t2val[(x, y)] = 0


# 根据一个点A的RGB值,与周围的8个点的RBG值比较,设定一个值N(0 <N <8),当A的RGB值与周围8个点的RGB相等数小于N时,此点为噪点
# G: Integer 图像二值化阀值
# N: Integer 降噪率 0 <N <8
# Z: Integer 降噪次数
# 输出
#  0:降噪成功
#  1:降噪失败
def clearNoise(image, N, Z):
    for i in range(0, Z):
        t2val[(0, 0)] = 1
        t2val[(image.size[0] - 1, image.size[1] - 1)] = 1

        for x in range(1, image.size[0] - 1):
            for y in range(1, image.size[1] - 1):
                nearDots = 0
                L = t2val[(x, y)]
                if L == t2val[(x - 1, y - 1)]:
                    nearDots += 1
                if L == t2val[(x - 1, y)]:
                    nearDots += 1
                if L == t2val[(x - 1, y + 1)]:
                    nearDots += 1
                if L == t2val[(x, y - 1)]:
                    nearDots += 1
                if L == t2val[(x, y + 1)]:
                    nearDots += 1
                if L == t2val[(x + 1, y - 1)]:
                    nearDots += 1
                if L == t2val[(x + 1, y)]:
                    nearDots += 1
                if L == t2val[(x + 1, y + 1)]:
                    nearDots += 1

                if nearDots < N:
                    t2val[(x, y)] = 1


def saveImage(filename, size):
    image = Image.new("1", size)
    draw = ImageDraw.Draw(image)

    for x in range(0, size[0]):
        for y in range(0, size[1]):
            draw.point((x, y), t2val[(x, y)])

    image.save(filename)

for i in range(1, 101):

    path = "1__get_image/" + str(i) +  ".png"
    image = Image.open(path)

    image = image.convert(L)
    twoValue(image, 198)
    clearNoise(image, 3, 1)
    path1 = "2__erzhihua_jiangzao/" + str(i) + ".jpg"
    saveImage(path1, image.size)

 

三:切割验证码:

  

#-*-coding:utf-8-*-


from PIL import Image



def smartSliceImg(img, outDir, ii,count=4, p_w=3):
    ‘‘‘
    :param img:
    :param outDir:
    :param count: 图片中有多少个图片
    :param p_w: 对切割地方多少像素内进行判断
    :return:
    ‘‘‘
    w, h = img.size
    pixdata = img.load()
    eachWidth = int(w / count)
    beforeX = 0
    for i in range(count):

        allBCount = []
        nextXOri = (i + 1) * eachWidth

        for x in range(nextXOri - p_w, nextXOri + p_w):
            if x >= w:
                x = w - 1
            if x < 0:
                x = 0
            b_count = 0
            for y in range(h):
                if pixdata[x, y] == 0:
                    b_count += 1
            allBCount.append({x_pos: x, count: b_count})
        sort = sorted(allBCount, key=lambda e: e.get(count))

        nextX = sort[0][x_pos]
        box = (beforeX, 0, nextX, h)
        img.crop(box).save(outDir + str(ii) + "_" + str(i) + ".png")
        beforeX = nextX

for ii in  range(1, 101):
    path = "2__erzhihua_jiangzao/" + str(ii) + ".jpg"
    img = Image.open(path)
    outDir = 3__qiege/
    smartSliceImg(img, outDir, ii,count=4, p_w=3)

 

四:训练:

    

#-*-coding:utf-8-*-

import numpy as np
import os
import time

from PIL import Image
from sklearn.externals import joblib
from sklearn.neighbors import KNeighborsClassifier


def load_dataset():
    X = []
    y = []
    for i in "23456789ABVDEFGHKMNPRSTUVWXYZ":
        target_path = "fenlei/" + i
        print(target_path)
        for title in os.listdir(target_path):
            pix = np.asarray(Image.open(os.path.join(target_path, title)).convert(L))
            X.append(pix.reshape(25 * 30))
            y.append(target_path.split(/)[-1])

    X = np.asarray(X)
    y = np.asarray(y)
    return X, y

def check_everyone(model):
    pre_list = []
    y_list = []
    for i in "23456789ABCDEFGHKMNPRSTUVWXYZ":
        part_path = "part/" + i
        for title in os.listdir(part_path):
            pix = np.asarray(Image.open(os.path.join(part_path, title)).convert(L))
            pix = pix.reshape(25 * 30)
            pre_list.append(pix)
            y_list.append(part_path.split(/)[-1])
    pre_list = np.asarray(pre_list)
    y_list = np.asarray(y_list)

    result_list = model.predict(pre_list)
    acc = 0
    for i in result_list == y_list:
        print(result_list,y_list,)

        if i == np.bool(True):
            acc += 1
    print(acc, acc / len(result_list))


X, y = load_dataset()
knn = KNeighborsClassifier()
knn.fit(X, y)
joblib.dump(knn, yipai.model)
check_everyone(knn)

 

六:测试:

    

# -*- coding: utf-8 -*-

import numpy as np
from PIL import Image
from sklearn.externals import joblib
import os

target_path = "1__get_image/"
source_result = []
for title in os.listdir(target_path):
    source_result.append(title.replace(.png,‘‘))


def predict(model):
    predict_result = []
    for q in range(1,101):
        pre_list = []
        y_list = []
        for i in range(0,4):
            part_path = "part1/" + str(q) + "_" + str(i) + ".png"
            # print(part_path)
            pix = np.asarray(Image.open(os.path.join(part_path)))
            pix = pix.reshape(25 * 30)
            pre_list.append(pix)
            y_list.append(part_path.split(/)[-1])
        pre_list = np.asarray(pre_list)
        y_list = np.asarray(y_list)

        result_list = model.predict(pre_list)
        print(result_list,q)


        predict_result.append(str(result_list[0] + result_list[1] + result_list[2] + result_list[3]))

    return predict_result


model = joblib.load(yipai.model)
predict_result = predict(model)
# print(source_result)
# print(predict_result)

 

python 验证码识别示例(二) 复杂验证码识别

标签:nal   filename   折线   dump   大小   int   path   训练   with   

原文地址:https://www.cnblogs.com/xuchunlin/p/9456593.html

(0)
(1)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!