标签：amp 实现 span dict 账号密码 += 一课 break style
第一步，实现 输入账号密码，显示账号欢迎：
username = input("username :") password = int(input("password :")) print("welcome ",username,"!!!!!!!!!")
第二步，判断账号密码是否正确：
userlist1=["a",123] username = input("username :") password = int(input("password :")) if (username == userlist1[0]) & (password==userlist1[1]): print("welcome ",username,"!!!!!!!!!") else:print("erro")
第三步，利用表，判断账号是否存在，且密码正确：
dict = {‘a‘: 123, ‘b‘: 234};
username = str(input("username :"))
password = int(input("password :"))
if (dict.__contains__(username)) & (password == dict.get(username)):
print("welcome ", username, "!!!!!!!!!")
else:
print("erro")
第四步，限制只能输入三次：
dict = {‘a‘: 123, ‘b‘: 234};
count=0
while count<3 :
username = input("username :")
password = int(input("password :"))
if (dict.__contains__(username)) & (password == dict.get(username)):
print("welcome ",username,"!!!!!!!!!")
break
else:
print("您已输入错误",count+1,"次，输入错误3次锁定")
count += 1
第五步，限制同一账号，只能输入错误3次，超出退出程序：
dict = {‘a‘: 123, ‘b‘: 234};
count=0
errolist=[]
while count<3 :
username = str(input("username :"))
errolist.append(username)
password = int(input("password :"))
if ( dict.__contains__( username) ) & (password==dict.get(username)):
print("welcome ",username,"!!!!!!!!!")
break
else:
print("您已输入错误",errolist.count(username),"次，输入错误3次锁定")
count = errolist.count(username)
第六步：限制同一账号，只能输入错误3次，限制所有错误5次，超出退出程序：
dict = {‘a‘: 123, ‘b‘: 234,‘c‘:456};
count=0
errolist=[]
blacklist=[]
while count<5 :
username = str(input("username :"))
errolist.append(username)
password = int(input("password :"))
if (blacklist.count(username)<3):
if ( dict.__contains__( username) ) & (password==dict.get(username)):
print("welcome ",username,"!!!!!!!!!")
break
else:
print("您已输入错误",errolist.count(username),"次，输入错误3次锁定")
blacklist.append(username)
count +=1
print(count)
if (count == 5) :
print("您尝试错误5次，程序将退出")
break
else:print("您已输入错误3次锁定")
标签：amp 实现 span dict 账号密码 += 一课 break style
原文地址：https://www.cnblogs.com/RayPy/p/9614016.html
