标签:内容 每日 结果 代码 运行 题目 isp col 文件内容
已知数据文件in.dat中有300个四位数,并调用readDat()函数把这些数存储数组a中,编写函数jsValue(),其功能是:求出所有这些四位数是素数的个数cnt,再把所有满足此条件的四位数依次存入数组b中,然后对数组b的按从小到大顺序排列,最后编写函数wirteDat()把数组b中的数输出到out.dat文件中。
7704,9774,3213,5845,7703,2902,1925,2584,7429,6646 3793,8640,4364,3032,9190,2498,6394,3796,2434,6791 5552,9052,9159,8245,7965,1071,8157,6526,2164,6767 4853,1174,4564,5427,7279,9832,3640,7897,3211,4788 6556,4781,2168,6014,7795,6536,9461,4287,8029,8303 2609,8795,8386,3911,8130,7268,1906,7345,3678,5823 8074,6963,7874,6066,4509,8976,1740,2026,7047,4730 9538,2193,8473,6729,4207,5095,4623,4933,6226,8098 1277,5480,1906,4109,9047,1986,5882,8444,1029,6515 2612,7297,6934,8495,7731,1625,1305,7953,7385,3620 7206,4549,5736,3131,6875,6917,6087,4640,5314,8646 6077,5677,7345,4143,1513,8101,2038,9879,3946,6643 7763,6108,4788,9055,8186,5416,5699,6733,5416,2320 2430,4772,9962,9676,1319,7767,7369,1411,3663,2876 2245,4810,5400,6045,1504,4178,7264,2763,7050,1490 8790,4014,9280,7105,7113,3600,8221,8203,6127,7313 1850,5983,9689,4102,1036,6375,5064,7188,9887,9800 6871,4856,2432,9562,3426,9013,5104,4724,4785,9953 5939,6668,8700,4730,9737,4055,6544,9763,1034,2855 8078,5111,4817,4593,9876,1189,2507,1197,1782,4347 7961,8612,9699,6108,4221,2489,8895,3672,8226,8724 6302,7624,7506,8568,4013,2785,3528,6712,1155,3150 1388,5803,6328,6841,5825,7802,2022,6290,1775,3652 9699,6573,8082,9016,4369,4002,3205,2688,8414,7572 2830,1231,3888,5137,5555,8976,2543,6542,8986,5921 5346,1368,2566,3304,4089,3880,1244,6650,6523,6123 1243,7488,5262,9992,3115,9270,6989,1595,1283,2645 4075,9471,7983,9093,7642,8847,5686,4168,8550,8941 5188,2290,3219,2853,6978,9053,5843,7153,6382,6289 3022,5591,9981,7296,2421,7328,9575,7586,1190,8504
#include <stdio.h> int a[300], b[300], cnt=0; void readDat() { FILE *fp; int i; fp = fopen("in.dat","r"); for(i = 0; i < 300; i++) { fscanf(fp, "%d,", &a[i]); } fclose(fp); } void writeDat() { FILE *fp; int i; fp = fopen("out.dat","w"); fprintf(fp, "%d\n", cnt); for(i = 0; i < cnt; i++) { fprintf(fp, "%d\n", b[i]); } fclose(fp); } int isP(int m) { int i; for(i = 2; i < m; i++) if(m % i == 0) return 0; return 1; } void jsValue() { int i,j; int temp; for(i=0;i<300;i++) { if(isP(a[i])) { b[cnt++]=a[i]; } } //方法一:冒泡排序 for(i=0;i<cnt;i++) { for(j=0;j<cnt-i-1;j++) { if(b[j]>b[j+1]) { temp=b[j]; b[j]=b[j+1]; b[j+1]=temp; } } } //方法二: /*for(i = 0; i < cnt; i++) { for(j = i + 1; j < cnt; j++) { if(b[i] > b[j]) { temp = b[j]; b[j] = b[i]; b[i] = temp; } } }*/ } void main() { int i; readDat(); jsValue(); writeDat(); printf("cnt=%d\n", cnt); for(i = 0; i < cnt; i++) { printf("b[%d]=%d\n", i, b[i]); } }
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原文地址:https://www.cnblogs.com/wutao666/p/9615110.html