使用ajax处理表单提交信息

<form id="form">
  <input type="text" name="user" id="user" placeholder="user">
  <br>
  <input type="password" name="password" id="password" placeholder="password">
  <br>
  <input type="file" name="file" id="file">
  <br>
  <!-- 自带回调函数的，就是会get提交 -->
  <input type="submit" name="submit" id="submit">
  <!-- 自带回调函数的，就是会重置 -->
  <input type="reset" name="reset" id="reset">
</form>

<script type="text/javascript">

  
  
  var submit = document.getElementById(‘submit‘);
  submit.addEventListener(‘click‘,(e)=>{
    //这样就能阻止默认的提交事件了
    e.preventDefault();
    // var user = document.getElementById(‘user‘);
    // var password = document.getElementById(‘password‘);
    // var file = document.getElementById(‘file‘);
    // // 获取所有的数据
    // console.log(user.value);
    // console.log(password.value);
    // console.log(file.value);

    //单纯获取value是没有用的，比如只能获取文件名
    var form = document.getElementById(‘form‘);
    var formData = new FormData(form);
    console.log(formData.get(‘user‘));
    console.log(formData.get(‘password‘));
    console.log(formData.get(‘file‘));

    //使用ajax
    var ajax = new XMLHttpRequest();
    ajax.open("POST", "/api/xxxxx", true);
    ajax.send(formData);
    ajax.onreadystatechange = ()=>{
      //如果成功，进行跳转
      setTimeout(()=>{
        location.href = ‘https://www.baidu.com‘;
      },2000);
    };

  })

</script>